4/5x-8=3
move -8 to the other side and add
4/5x=3+8
4/5x=11
move 5x to the other side and multiply
4=5x*11
4=55x
4/55=x
They are 7 points away from each other.
8÷2/7
8/1÷2/7
8/1*7/2
56/2
28
Hope this helps :)
Answer:
The proportion of student heights that are between 94.5 and 115.5 is 86.64%
Step-by-step explanation:
We have a mean 
and a standard deviation 
. For a value x we compute the z-score as 
, so, for x = 94.5 the z-score is (94.5-105)/7 = -1.5, and for x = 115.5 the z-score is (115.5-105)/7 = 1.5. We are looking for P(-1.5 < z < 1.5) = P(z < 1.5) - P(z < -1.5) = 0.9332 - 0.0668 = 0.8664. Therefore, the proportion of student heights that are between 94.5 and 115.5 is 86.64%
Step-by-step explanation:
the option A is the binomial.
hope this helps you.
