All you need to do is use the formula to solve. What I do is I plug in the information that I know, and then I just solve. In this case it would be:
V= (4)
- pie(3.14)*4.8(cubed)
3
I hope I was a good help, and if you still need help, come to my page and ask the question on specifically what you need help with. :D
Answer:
1) is not possible
2) P(A∪B) = 0.7
3) 1- P(A∪B) =0.3
4) a) C=A∩B' and P(C)= 0.3
b) P(D)= 0.4
Step-by-step explanation:
1) since the intersection of 2 events cannot be bigger than the smaller event then is not possible that P(A∩B)=0.5 since P(B)=0.4 . Thus the maximum possible value of P(A∩B) is 0.4
2) denoting A= getting Visa card , B= getting MasterCard the probability of getting one of the types of cards is given by
P(A∪B)= P(A)+P(B) - P(A∩B) = 0.6+0.4-0.3 = 0.7
P(A∪B) = 0.7
3) the probability that a student has neither type of card is 1- P(A∪B) = 1-0.7 = 0.3
4) the event C that the selected student has a visa card but not a MasterCard is given by C=A∩B' , where B' is the complement of B. Then
P(C)= P(A∩B') = P(A) - P(A∩B) = 0.6 - 0.3 = 0.3
the probability for the event D=a student has exactly one of the cards is
P(D)= P(A∩B') + P(A'∩B) = P(A∪B) - P(A∩B) = 0.7 - 0.3 = 0.4
Answer:
True, since 1 is 1/1, which is 100%
<em>Hope that helps! :)</em>
Step-by-step explanation:
Answer: Hi hope your new account doesn't malfunction.
Once we find what x and y is, that's where they intercept and we can write that as an ordered pair as (x,y)
Now we need to find what y is. So let's put x into the original first equation
3x+4y=16
3(4)+4y=16
12+4y=16 ---Subtract 12 from both sides
4y=4 ---Divide both sides by 4
y=1
Alright, so our ordered pair is (4,1)
