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Masteriza [31]
3 years ago
12

A line has this equation: y=-3x+7

Mathematics
1 answer:
Vadim26 [7]3 years ago
5 0

Given:

The equation of line is y=-3x+7.

A line is parallel to given equation and passes through the point (-4,-8).

To find:

The equation of parallel line.

Solution:

The equation of a line is

y=-3x+7

On comparing this equation with y=mx+b, we get

m=-3

So, slope of given line is -3.

We know that, slopes of parallel lines are equal. It means, the slope of the parallel line is also -3.

The parallel line passes through (-4,-8) and having slope -3. So, the equation of line is

y-y_1=m(x-x_1)

y-(-8)=(-3)(x-(-4))

y+8=(-3)(x+4)

y+8=-3x-12

y=-3x-12-8

y=-3x-20

Therefore, the equation of parallel line is y=-3x-20.

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A surveyor, Toby, measures the distance between two landmarks and the point where he stands. He also measured the angles between
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What we know so far:
Side 1 = 55m
Side 2 = 65m
Angle 1 = 40°
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What we are looking for:
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The distance x = ?

We need to look for Toby's angle so that we can solve for the distance x by assuming that the whole figure is a SAS (Side Angle Side) triangle.

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Since we already have Toby's angle, we can now solve for the distance x by using the law of cosines r² = p²+ q²<span>− 2pq cos R where r is x, p is Side1, q is Side2, and R is Toby's Angle.
</span>
x² = Side1² + Side2² - 2[(Side1)(Side2)] cos(Toby's Angle)
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