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3 years ago

PLEASE HELP!! I will mark brainliest

Mathematics

2 answers:

xxTIMURxx [149]3 years ago

5 0

Answer:

first and sixth

Step-by-step explanation:

they match

Arisa [49]3 years ago

4 0

Answer:

the top one and bottom one

Step-by-step explanation:

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Rewrite the following polynomial in standard form<br><br> 1<br> 3<br> - 1 + x2

kifflom [539]

12 + x^2..............

7 0

2 years ago

A triangle has an area of 9m2 and a base of 6m. how do I find the height of this triangle?

KonstantinChe [14]

You know the triangle has a base of 6 meters, and that the formula to find the area of a triangle is 1/2bh or one-half of the base times the height. So, you would plug in 9 meters squared=one half of six times h, or 9m^2=1/2(6)*(h). In simplifying this, you would get 3h=9m^2. Divide both sides by three and get h=3. Hope this helps, and if you need any further explanations, please let me know!

8 0

3 years ago

a line has a slope of 2 and passes through the point of 3,9. wat is the equation of the line in slope intercept form

7nadin3 [17]

The equation for a line that passes through the point of (3, 9) and has a slope of 2 in slope intercept form is y=2x+3

6 0

3 years ago

Emma borrowed $89.40 from her sister. She determines that she can pay her back the total over six months. Which number reflects

omeli [17]

Answer:

$14.9

Step-by-step explanation:

Step one:

given data

we are told that Emma borrowed $89.40 from her sister to pay her back in 6 months.

let us solve for the amount she is to pay her sister every month.

amount to be paid per month= 89.40/6

=$14.9

So that every month she pays back her sister $14.9

we don't know her balance but every month there will be a deduction.

Hence the monthly change in her balance is reflected by a deduction of $14.9

5 0

3 years ago

Find a power series representation of e^x sin(x)

liberstina [14]

The Taylor series is defined by:
$f(x) = \sum \frac{f^n (a)}{n!} (x-a)^n$

Let a = 0.
Then its just a matter of finding derivatives and determining how many terms is needed for the series.

Derivatives can be found using product rule:
$f^n (x) = e^x g^{n-1} (x) + e^x g^n (x) \\ g^0 (x) = sin x$

Do this successively to n = 6.
$f^1 (x) = e^x (sinx +cos x) \\ f^2 (x) = e^x (2cos x) \\ f^3 (x) = e^x(2cos x - 2sin x) \\ f^4 (x) = e^x (-4 sin x) \\ f^5 (x) = e^x(-4sinx -4cos x) \\ f^6(x) = e^x(-8cos x)$

Plug in x=0 and sub into taylor series:
$e^x sin x = x+x^2 +\frac{x^3}{3} -\frac{x^5}{30}-\frac{x^6}{90}...$

If more terms are needed simply continue the recursive derivative formula and add to taylor series.

6 0

3 years ago