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3 years ago

9

5/10 of a student in Sam's class are girls of the girls 1/5 of them are classes what fraction of the students were glasses using

model and check your multiplication

2 answers:

Tema [17]3 years ago

8 0

Answer:

1

Step-by-step explanation:

Alexeev081 [22]3 years ago

6 0

One, 1, One, 1 One, 1

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Write a line in slope-intercept from that goes through the point (2, 5) with a slope of 1/2

nalin [4]

Answer:

y=1/2x+5

Step-by-step explanation:

The formula is y=mx+b.

m is the slope, and b is the y-intercept.

1/2 is the slope, and 5 is the y-intercept.

y=1/2x+5.

-hope it helps

6 0

2 years ago

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Find the m∠CDE, if m∠BCA = 90° and m∠BAC =57°.<br><br> 33°<br> 43°<br> 57°<br> 67°

garri49 [273]

Answer:

33

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Please answer my questions is really easy but idk

GrogVix [38]

Given:

$m \angle A B D=96^{\circ}$

$m \angle 2 =m \angle 1+ 26^{\circ}$

To find:

$m \angle 1$

Solution:

$m \angle DBC+ m \angle CBA = m \angle ABD$

$m \angle 1+ m \angle 2 = m \angle ABD$

Substitute $m \angle 2 =m \angle 1+ 26^{\circ}$ .

$m \angle 1+ m \angle 1 + 26^\circ = 96^\circ$

$2m \angle 1+ 26^\circ = 96^\circ$

Subtract 26° from both sides.

$2m \angle 1+ 26^\circ -26^\circ = 96^\circ -26^\circ$

$2m \angle 1 = 70^\circ$

Divide by 2 on both sides, we get

$m \angle 1=35^{\circ}$

Therefore, m∠1 = 35°.

8 0

4 years ago

Read 2 more answers

A board game that normally sells for $34.95 is on sale at an 18% discount. What is the sale price of the board game?

fomenos

34.95 x 18%= 6.29

34.95-6.29= 28.66

$28.66 is the sale price

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3 years ago

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The angle θ1\theta_1 θ 1 theta, start subscript, 1, end subscript is located in Quadrant II\text{II} II start text, I, I, end

melomori [17]

Answer:

$\dfrac{3\sqrt{13}}{11}$

Step-by-step explanation:

Given that the angle $\theta_1$ is located in Quadrant II; and

$\cos(\theta_1)=-\dfrac{2}{11}$

In Quadrant II, x is negative and y is positive.

$\cos(\theta)=\dfrac{Adjacent}{Hypotenuse},\sin(\theta)=\dfrac{Opposite}{Hypotenuse}\\$Adjacent=-2\\Hypotenuse=11\\$

To find $\sin(\theta_1)$ , we first determine the opposite angle of $\theta_1$ .

This will be done using the Pythagoras theorem.

$Hypotenuse^2=Opposite^2+Adjacent^2\\11^2=Opposite^2+(-2)^2\\Opposite^2=121-4=117\\Opposite=\sqrt{117}=3\sqrt{13}$

Therefore:

$\sin(\theta_1)=\dfrac{Opposite}{Hypotenuse}=\dfrac{3\sqrt{13}}{11}$

6 0

3 years ago