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Serhud [2]
3 years ago
9

5/10 of a student in Sam's class are girls of the girls 1/5 of them are classes what fraction of the students were glasses using

model and check your multiplication
​
Mathematics
2 answers:
Tema [17]3 years ago
8 0

Answer:

1

Step-by-step explanation:

Alexeev081 [22]3 years ago
6 0

One, 1, One, 1 One, 1

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How to evaluate question number 4
ANTONII [103]

There are 2 ways that spring to mind.

One is to use the definition of the derivative at a point:

f'(c)=\displaystyle\lim_{x\to c}\frac{f(x)-f(c)}{x-c}

In this case, c=0 and f(x)=\sqrt{5-x}. Then

f'(x)=-\dfrac1{2\sqrt{5-x}}\implies f'(0)=\displaystyle\lim_{x\to0}\frac{\sqrt{5-x}-\sqrt5}x=-\dfrac1{2\sqrt5}

- - -

If you don't know about derivative yet (I would think you do, considering this is for a midterm in AP Calc, but I digress), the other way is to rely on algebraic manipulation. Multiply the numerator and denominator by the conjugate of the numerator to get

\dfrac{\sqrt{5-x}-\sqrt5}x\cdot\dfrac{\sqrt{5-x}+\sqrt5}{\sqrt{5-x}+\sqrt5}=\dfrac{\left(\sqrt{5-x}\right)^2-\left(\sqrt5\right)^2}{x\left(\sqrt{5-x}+\sqrt5\right)}=-\dfrac x{x\left(\sqrt{5-x}+\sqrt5\right)}=-\dfrac1{\sqrt{5-x}+\sqrt5}

This is continuous at x=0, so the limit is the value of the expression at x=0:

\displaystyle\lim_{x\to0}\frac{\sqrt{5-x}-\sqrt5}x=-\lim_{x\to0}\frac1{\sqrt{5-x}+\sqrt5}=-\frac1{2\sqrt5}

5 0
3 years ago
1. Each of three friends—Lin, Jada, and Andre—had the goal of raising $40.
viva [34]
Jin raised 40$ since it was his goal and he reached it
3 0
3 years ago
Read 2 more answers
See image for question.​
Ostrovityanka [42]

Answer:

  • See below

Step-by-step explanation:

#3

  • P(A) = 3/8
  • P(B) = 2/7

(i)

  • P(A and B) = P(A) * P(B) = 3/8*2/7 = 3/28

(ii)

  • P(A or B) = P(A) + P(B) - P(A and B) = 3/8 + 2/7 - 3/28 = 1/56(21 + 16 - 6) = 31/56

(iii)

  • P(not A and not B) = P(not A) * P(not B) = (1 - 3/8)*(1 - 2/7) = 5/8*5/7 = 25/56

<u>Another way:</u>

  • P(not A and not B) = 1 - P(A or B) = 1 - 31/56 = 25/56

#4

Outcomes with two fair coins: TT, TH, HT, HH

Outcomes with normal dice: 1 to 6

a)

  • P(odd number) = 3/6 = 1/2

b)

  • P(two heads and an even number) = 1/4*3/6 = 1/8

c)

  • P(head and tail) = 1/2
  • P(prime) = 3/6 = 1/2 (primes are 2, 3 and 5)
  • P(head, tail and prime) = 1/2*1/2 = 1/4

d)

  • P(two tails and odd number) = 1/4*3/6 = 1/8
4 0
2 years ago
Find the value of x in the parallelogram
lord [1]

Answer:

72 = x

Step-by-step explanation

154 is one of the degrees for that angle. And I seen 82 for the other one.

All you have to do is subtract 154 and 82 and you get 72.

8 0
2 years ago
6(a + 5) = 42<br><br> ...................................
Elan Coil [88]
It’s 2 if I did my math right because I did it 2 tones and both of the times I got 2
5 0
3 years ago
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