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PilotLPTM [1.2K]
3 years ago
5

What is the rule for the nth term for number sequence 2;5;7;12;19

Mathematics
1 answer:
Len [333]3 years ago
7 0
Add the two previous terms together to get your next answer: 2 + 5 = 7 , 7 + 12 = 19.
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Mrs. Santos baked 25 cookies. 3 fifths of the cookies were oatmeal. How many oatmeal cookies did Mrs. Santos bake?
grigory [225]

Answer: 15 oatmeal cookies.

Step-by-step explanation:

There were 25 cookies baked.

Out of these, 3/5 are oatmeal cookies.

The amount of actual oatmeal cookies is:

= fraction of oatmeal cookies * total number of cookies

= 3/5 * 25

= 75 / 5

= 15 oatmeal cookies.

7 0
3 years ago
Two sides of a triangle have lengths 18cm and 40cm describe the possible lengths of the third side
Paraphin [41]

Answer:

Step-by-step explanation:

a taingle adds up to 180 degrees if that helps

5 0
3 years ago
Consider the equation below -2(5x + 8) = 14 + 6x complete the statements below with the process used to achieve steps 1-4
Ad libitum [116K]

Step-by-step explanation:

1. Distribute the -2. multiply-2 with 5x and 8. it will be -10x-16=14+6x. For me, i make small numbers negative or positive than big ones. Add 16 to both sides. it will be -10x=30+6x. Subtract 6x. -10x-6x=-16x. Divide both sides by 16. x=30/16= 1 and 14/16

6 0
3 years ago
1) Which of the following is a surd ? a) 64 b) 6 root 64 c) 4 root 64 d) 3 root 64
Mashcka [7]

Answer:

  \text{c) }\sqrt[4]{64}=2\sqrt[4]{4}

Step-by-step explanation:

\text{a) }64\qquad\text{an integer; not a surd}\\\\\text{b) }\sqrt[6]{64}=2\qquad\text{an integer; not a surd}\\\\\text{c) }\sqrt[4]{64}=2\sqrt[4]{4}\qquad\textbf{a surd}\\\\\text{d) }\sqrt[3]{64}=4\qquad\text{an integer; not a surd}

5 0
3 years ago
In Ryan Corporation, the first shift produced 5 1/2 times as many lightbulbs as the second shift. If the total lightbulbs produc
Andru [333]

Answer:

13750

Step-by-step explanation:

Let 'x' be the number of bulbs produced in second shift

Number of bulbs produced in 1st shift= 5.5x

Total number of bulbs= 5.5x+x

16250=5.5x+x

x=2500

Number of bulbs produced in shift 1= 5.5×2500

                                                            = 13750

7 0
3 years ago
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