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White raven [17]
3 years ago
15

John and Kamira are playing a game. John scores - 5 in the first round, while Kamira scores 7.

Mathematics
1 answer:
disa [49]3 years ago
8 0

Answer:

the sum of John's score and Kamira's score

Step-by-step explanation:

-5 + 7 = 2

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The number of cows a farmer has on his farm over several years can be modeled by an arithmetic sequence. During the 2nd, 5th, an
Leni [432]

Answer: im not sure

Step-by-step explanation:

i have that same problem and its due in ten min :( sorry

8 0
3 years ago
Mary charges $5.60 per square foot of carpet, plus a $150 installation fee. How much should Mary charge the customer to the near
devlian [24]

Answer:

Step-by-step explanation:

Total = t

Square feet = f

t = 5.6f + 150

you didnt say how many square feet the customer wanted, but just plug it in for f and t is the answer

6 0
3 years ago
Find the value of the constant k that makes the function continuous. ​g(x)equals=startset start 2 by 2 matrix 1st row 1st column
tiny-mole [99]
You seem to have
.. g(x) = {(2x^2 -4x -16)/(x -4) . . . x ≠ 4
.. .. .. .. ..{ kx -16 . . . . . . . . . . . . . . x=4

The first expression can be simplified to
.. (2x^2 -4x -16)/(x -4) = 2(x +2)(x -4)/(x -4) = 2(x +2) . . . . x ≠ 4
At x=4, this simplified version has the value
.. 2(4 +2) = 12

To make the alternate definition of g(x) have that same value at x=4, we must have
.. k*4 -16 = 12
.. 4k = 28
,, k = 7

The constant k must be 7 for the function to be continuous at x=4.
7 0
3 years ago
Read 2 more answers
[20 Points] I need help with these questions:
I am Lyosha [343]

Slope-intercept form:

y = mx + b

"m" is the slope, "b" is the y-intercept (the y value when x = 0)

You need to find "m" and "b"


1.) For lines to be perpendicular, their slopes have to be the opposite/negative reciprocal (flipped sign and number)

For example:

slope is 2

perpendicular line's slope is -1/2

slope is -2/3

perpendicular line's slope is 3/2


The given line's slope is -4, so the perpendicular line's slope is 1/4.

y = 1/4x + b

To find "b", you can plug in the point (4, -2) into the equation

y = 1/4x + b

-2 = 1/4(4) + b

-2 = 1 + b

-3 = b


y=\frac{1}{4} x-3


2.) To find "m", use the slope formula and plug in the two points:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

m=\frac{8-(-1)}{-2-4}

m=\frac{8+1}{-2-4}

m=\frac{9}{-6} =-\frac{3}{2}


y = -3/2x + b

Plug in one of the points to find "b"

y = -3/2x + b

-1 = -3/2(4) + b

-1 = -6 + b

5 = b


y=-\frac{3}{2}x +5


3.) y-intercept: 5 (since the given equation's y-intercept is 5)

I'm confused with what they mean by "steep", so I'll try to update this later unless someone else has an answer


So I looked it up, and it says that a steep slope is a line that is more vertical [if that makes sense]. So you could do a slope of +3 (more than 3, like 4, 5, 6...) because the given line's slope is 3, and you need a new line that is more steeper(vertical)

3 0
3 years ago
Initially 15 grams of salt are dissolved into 25 liters of water. Brine with concentration of salt 4 grams per liter is added at
Alla [95]

Answer:

a) dx/dt = 600 - 6x

b) x = 100 - 4.12((e⁻ ⁽⁶ᵗ ⁻ ³•⁰²⁾)

c) The mass of salt in the tank attains the value of 20 g at time, t = 0.227 min = 13.62 s

Explanation:

Taking the overall balance, since the total Volume of the setup is constant, then flowrate in = flowrate out

Let the concentration of salt in the tank at anytime be C

Let the concentration of salt entering the tank be Cᵢ

Let the concentration of salt leaving the tank be C₀ = C (Since it's a well stirred tank)

Let the flowrate in be represented by Fᵢ

Let the flowrate out = F₀ = F

Fᵢ = F₀ = F = 6 L/min

a) Then the component balance for the salt

Rate of accumulation = rate of flow into the tank - rate of flow out of the tank

dx/dt = Fᵢxᵢ - Fx

Fᵢ = 6 L/min, C = 4 g/L, F = 6 L/min

dC/dt = 24 - 6C

dx/dt = 25 (dC/dt), (dC/dt) = (1/25) (dx/dt) and C = x/25

(1/25)(dx/dt) = 24 - (6/25)x

dx/dt = 600 - 6x

b) dC/dt = 24 - 6C

dC/(24 - 6C) = dt

∫ dC/(24 - 6C) = ∫ dt

(-1/6) In (24 - C) = t + k (k = constant of integration)

In (24 - 6C) = -6t - 6k

-6k = K

In (24 - 6C) = K - 6t

At t = 0, C = 15 g/25 L = 0.6 g/L

In (24 - 6(0.6)) = K

In 20.4 = K

K = 3.02

So, the equation describing concentration of salt at anytime in the tank is

In (24 - 6C) = K - 6t

In (24 - 6C) = 3.02 - 6t

24 - 6C = e⁻ ⁽⁶ᵗ ⁻ ³•⁰²⁾

6C = 24 - (⁻⁽⁶ᵗ ⁻ ³•⁰²⁾)

C = 4 - ((e⁻⁽⁶ᵗ ⁻ ³•⁰²⁾)/6

C = 4 - (e⁻ ⁽⁶ᵗ ⁻ ³•⁰²⁾)/6)

But C = x/25

x/25 = 4 - (e⁻ ⁽⁶ᵗ ⁻ ³•⁰²⁾)/6)

x = 100 - 4.12((e⁻ ⁽⁶ᵗ ⁻ ³•⁰²⁾)

c) when x = 20 g

20 = 100 - 4.12(e⁻ ⁽⁶ᵗ ⁻ ³•⁰²⁾)

80 = (e⁻ ⁽⁶ᵗ ⁻ ³•⁰²⁾)

- (6t - 3.02) = In 80

- (6t - 3.02) = 4.382

(6t - 3.02) = -4.382

6t = -4.382 + 3.02

t = 1.362/6 = 0.227 min = 13.62 s

4 0
3 years ago
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