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Montano1993 [528]
3 years ago
8

2/10 convert to a decimal​??????????

Mathematics
2 answers:
laila [671]3 years ago
8 0

Answer:

0.2

Step-by-step explanation:

Maksim231197 [3]3 years ago
6 0

Answer:

<h3>O.2</h3>

Step-by-step explanation:

Simply divide the numerator by the denominator.

<h3>= 2/10</h3>

<h3>= 2÷10</h3>

<h3><u>=</u><u> </u><u> </u><u>0.2</u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u></h3>

<h3>I hope it helps</h3>
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3 years ago
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svetoff [14.1K]

Step-by-step explanation:

The angles on the same side of the parallel lines and the transversal are called corresponding angles.

Corresponding angles are congruent

So 11x+1 = 10x+10

x = 10-1 = 9

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7 0
2 years ago
Domino's Pizza cuts their Large pizza into 8 equal slices. What is the area of one of the slices if diameter is 16 inches?
Ksju [112]

Answer:

25.1325

Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
g A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of pa
adoni [48]

Complete Question

A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of parts had a mean of 1.6 millimeters with a standard deviation of 0.03 millimeters. what standard deviation will be needed to achieve a process capability index f 2.0?

Answer:

The value required is  \sigma =  0.0133

Step-by-step explanation:

From the question we are told that

   The upper specification is  USL  =  1.68 \ mm

    The lower specification is  LSL  = 1.52  \  mm

     The sample mean is  \mu =  1.6 \  mm

     The standard deviation is  \sigma =  0.03 \ mm

Generally the capability index in mathematically represented as

             Cpk  =  min[ \frac{USL -  \mu }{ 3 *  \sigma }  ,  \frac{\mu - LSL }{ 3 *  \sigma } ]

Now what min means is that the value of  CPk is the minimum between the value is the bracket

          substituting value given in the question

           Cpk  =  min[ \frac{1.68 -  1.6 }{ 3 *  0.03 }  ,  \frac{1.60 -  1.52 }{ 3 *  0.03} ]

=>      Cpk  =  min[ 0.88 , 0.88  ]

So

         Cpk  = 0.88

Now from the question we are asked to evaluated the value of  standard deviation that will produce a  capability index of 2

Now let assuming that

         \frac{\mu - LSL  }{ 3 *  \sigma } =  2

So

         \frac{ 1.60 -  1.52  }{ 3 *  \sigma } =  2

=>    0.08 = 6 \sigma

=>     \sigma =  0.0133

So

        \frac{ 1.68  - 1.60 }{ 3 *  0.0133 }

=>      2

Hence

      Cpk  =  min[ 2, 2 ]

So

    Cpk  = 2

So    \sigma =  0.0133 is  the value of standard deviation required

3 0
3 years ago
A set of data already has the values 11, 14, 23, and 16. What value would have to be added to the set for the mean of the five n
KonstantinChe [14]
1) Take 18 and multiply it by 5 = 90
2) Then subtract 26 = 64
3) Then subtract 18 = 46
4) Then subtract 12 = 34
5)  Then subtract 8 = 26
 
The answer is 26.

5 0
3 years ago
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