7x(x+1.8)=0 Please find x!

one tank is filling at a rate of 3/4 per gallon per 2/3 minute .a second tank is at a 5/8 gallon per 1 half gallon per 1/2 minut

Bingel [31]

$recall\ that\implies \cfrac{\frac{a}{b}}{\frac{c}{{{ d}}}}\implies \cfrac{a}{b}\cdot \cfrac{{{ d}}}{c}\qquad thus
\\ \quad \\

\cfrac{\frac{3g}{4}}{\frac{2m}{3}}\implies \cfrac{3g}{4}\cdot \cfrac{3}{2m}\implies \cfrac{\square ?}{\square ?}
\\-------------\\
\cfrac{\frac{5g}{8}}{\frac{1m}{2}}\implies \cfrac{5g}{8}\cdot \cfrac{2}{1m}\implies \cfrac{\square ?}{\square ?}$

so... you tells us, which filling rate is the bigger and thus faster one?

6 0

2 years ago

can some one explain to me how fractions work who ever explains it well gets brainliest, adding, subtracting, multiplying, divid

Ludmilka [50]

Adding: When adding fractions, you want to make sure that the denominator is the same for both fractions. If they are already the same, just add both the numerators to get the answer. For example,
$\frac{3 }{5} + \frac{1}{5} = \frac{4}{5}$
If the denominator is different in both fractions, you have to find the least common denominator, or LCD. The LCD is the smallest number that both denominators can multiply into. For example, say you need to find
$\frac{1}{6} + \frac{1}{3}$

Multiply both the numerator and the denominator of (1/3) by 2 to get (2/6). This way, the denominators are the same and you can find the answer.
$\frac{1}{6} + \frac{2}{6} = \frac{3}{6}$
In the case that one denominator does not go into the other, find the smallest number they both multiply into. For example,
$\frac{1}{3 } + \frac{1}{4}$
Here, the smallest number that both 4 and 3 multiply into is 12. Multiply both fractions by the correct amount to make both denominators 12. It would then become
$\frac{4}{12} + \frac{3}{12} = \frac{7}{12}$
Subtraction: follow the same rules as addition, except subtract the numerators instead of adding them.

Multiplication: multiply both numerators and both denominators.
$\frac{2}{3} \times \frac{4}{5} = \frac{8}{15}$
Division: Flip one of the fractions and multiply.
$\frac{2}{3} \div \frac{4}{5}$
Becomes
$\frac{2}{3} \times \frac{5}{4} = \frac{10}{12} = \frac{5}{6}$
Hope this explains it all. Let me know if you have any questions :)

4 0

3 years ago

1. 51=-7x-6(-4x+17) 2. 184=-2x+6(5x-16) Solve for x

Afina-wow [57]

Answer:

1- x= 9

2- x= 10...............

4 0

2 years ago

Tristan is working on dilating rectangles. Rectangle ABCD is dilated by a factor of 3. The resulting rectangle WXYZ has an area

zloy xaker [14]

Answer:

Tristan is correct, because he needs to find the possible dimensions for rectangle WXYZ and then divide each dimension by 3.

Step-by-step explanation:

The rectangle ABCD is dilated by a factor of 3 to get the rectangle WXYZ whose area is found to be 72 cm².

Let the dimensions of the dilated rectangle WXYZ are a cm by b cm.

So, ab = 72 ........... (1)

Now, the dimensions of the original rectangle are 3 times lesser than the dimensions of rectangle WXYZ.

So, the area of rectangle ABCD will be $(\frac{a}{3} \times \frac{b}{3}) = \frac{ab}{9} = \frac{72}{9} = 8$ cm² {from equation (1)}

Therefore, Tristan is correct, because he needs to find the possible dimensions for rectangle WXYZ and then divide each dimension by 3. (Answer)

8 0

2 years ago

What is the answer to this? −1.3≥2.9−0.6r

Karolina [17]

Answer:

Inequality Form:

r ≥ 7

Interval Notation:

[7, ∞)

Step-by-step explanation:

−1.3 ≥ 2.9 − 0.6r

Rewrite so r is on the left side of the inequality.

2.9 − 0.6r ≤ −1.3

Move all terms not containing r to the right side of the inequality.

Subtract 2.9 from both sides of the inequality.

−0.6r ≤ −1.3 − 2.9

Subtract 2.9 from −1.3.

−0.6r ≤ −4.2

Divide each term by −0.6 and simplify.

Divide each term in −0.6r ≤ −4.2 by −0.6. When multiplying or dividing both sides of an

inequality by a negative value, f lip the direction of the inequality sign.

−0.6r /−0.6 ≥ −4.2 /−0.6

Cancel the common factor of −0.6.

−4.2

r ≥ ______

−0.6

Divide −4.2 by −0.6.

r ≥ 7

The result can be shown in multiple forms.

Inequality Form:

r ≥ 7

Interval Notation:

[7, ∞)

6 0

2 years ago