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2 years ago

8

Suppose you are given the following rational function: y= 2x-4/x^2-4. What is the corresponding range value when the domain valu

e is {4}?

2 answers:

ipn [44]2 years ago

6 0

Answer:

1/3

Step-by-step explanation:

exis [7]2 years ago

5 0

Answer:

1/3

Step-by-step explanation:

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Need help asap, thanks!

il63 [147K]

Answer:

b option

Step-by-step explanation:

Refer to the attachment.

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6 0

2 years ago

If there is an increase in the money supply that causes prices to rise and

andrew-mc [135]

Answer:

The answer is B.

Step-by-step explanation:

5 0

3 years ago

If g(x)= 2x-1, and h(x)= square root of x, find (goh)(9)

loris [4]

(goh) = 2(x^1/2)-1
(goh)(9) = 2(9^1/2)-1
= 2(3)-1
= 6-1
= 5
(goh)(9) = 5

5 0

2 years ago

Read 2 more answers

Line passing through (2,5) and the m= -5/6

kiruha [24]

Answer:

y - 5 = (-5/6)(x - 2)

y - 5 = (-5/6)x + 10/6

y - 30/6 = (-5/6)x + 10/6

y = (-5/6)x + 20/3

Step-by-step explanation:

5 0

2 years ago

Use properties of limits and algebraic methods to find the limit, if it exists. (If the limit is infinite, enter '[infinity]' or

soldi70 [24.7K]

Answer:

The limit of this function does not exist.

Step-by-step explanation:

$\lim_{x \to 3} f(x)$

$f(x)=\left \{ {{9-3x} \quad if \>{x \>< \>3} \atop {x^{2}-x }\quad if \>{x\ \geq \>3 }} \right.$

To find the limit of this function you always need to evaluate the one-sided limits. In mathematical language the limit exists if

$\lim_{x \to a^{-}} f(x) = \lim_{x \to a^{+}} f(x) =L$

and the limit does not exist if

$\lim_{x \to a^{-}} f(x) \neq \lim_{x \to a^{+}} f(x)$

Evaluate the one-sided limits.

The left-hand limit

$\lim_{x \to 3^{-} } 9-3x= \lim_{x \to 3^{-} } 9-3*3=0$

The right-hand limit

$\lim_{x \to 3^{+} } x^{2} -x= \lim_{x \to 3^{+} } 3^{2}-3 =6$

Because the limits are not the same the limit does not exist.

8 0

3 years ago