for detailed and showed working my answer is in the picture above
lcm = 504
hcf = 8
A.) Highest degree of the equation is 4. Therefore it is quartic. Quintic is for polynomial with highest degree 5. Quadratic with highest degree 2 and cubic with highest degree 3.
Answer:
∠5 = 60°
∠6 = 30°
∠7 = 120°
Step-by-step explanation:
Since the polygon is regular, you know that the central angle (7) is 1/3 of the circle, or 120°. The angle 5 is half that measure, so is 60°, and the angle 6 is the complement of angle 5, so is 30°. (Angle 6 is also half the inscribed angle at each vertex, said inscribed angle being 120°/2 = 60°.)
∠5 = 60°
∠6 = 30°
∠7 = 120°
Width: x
length: x + 4
Equation: 2(x + x + 4) = 56
2(2x + 4) = 56
4x + 8 = 56
4x = 48, x = 12
Width = 12, 12 + 4 = length
Solution: the length is 16 inch
Notice that
11/12 = 1/6 + 3/4
so that
tan(11π/12) = tan(π/6 + 3π/4)
Then recalling that
sin(x + y) = sin(x) cos(y) + cos(x) sin(y)
cos(x + y) = cos(x) cos(y) - sin(x) sin(y)
⇒ tan(x + y) = (tan(x) + tan(y))/(1 - tan(x) tan(y))
it follows that
tan(11π/12) = (tan(π/6) + tan(3π/4))/(1 - tan(π/6) tan(3π/4))
tan(11π/12) = (1/√3 - 1)/(1 + 1/√3)
tan(11π/12) = (1 - √3)/(√3 + 1)
tan(11π/12) = - (√3 - 1)²/((√3 + 1) (√3 - 1))
tan(11π/12) = - (4 - 2√3)/2
tan(11π/12) = - (2 - √3) … … … [A]
