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Furkat [3]
3 years ago
7

Andre says I'm multiplied 4 by 5 then cubed the results select all expressions are equal Andres answer a 4×5 to the power of 3B4

times five to the power of 3C4 times five to the power of 2D5 to the power of three times for E 20 to the power of 3F 500 G 8000
Mathematics
1 answer:
Charra [1.4K]3 years ago
5 0

Answer:

(4 * 5)^3 ;

8000

Step-by-step explanation:

Andre's statement :

Multiply 4 by 5 = 4 * 5 = 20

Cube the result = 20³

The equal expression from the option :

A.) (4 * 5)^3

Also, (4 * 5)^3 = 20^3 = 20 * 20 *20 = 8000

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Xelga [282]
That should be the answer

8 0
3 years ago
A stack of bricks is 3 1/2 feet high.
ololo11 [35]
Divide 42 inches by the total amount of inches in one brick
why you are dividing by 42 inches is because 3 1/2 ft is equal to 42 inches
4 0
3 years ago
If <img src="https://tex.z-dn.net/?f=%5Crm%20%5C%3A%20x%20%3D%20log_%7Ba%7D%28bc%29" id="TexFormula1" title="\rm \: x = log_{a}(
timama [110]

Use the change-of-basis identity,

\log_x(y) = \dfrac{\ln(y)}{\ln(x)}

to write

xyz = \log_a(bc) \log_b(ac) \log_c(ab) = \dfrac{\ln(bc) \ln(ac) \ln(ab)}{\ln(a) \ln(b) \ln(c)}

Use the product-to-sum identity,

\log_x(yz) = \log_x(y) + \log_x(z)

to write

xyz = \dfrac{(\ln(b) + \ln(c)) (\ln(a) + \ln(c)) (\ln(a) + \ln(b))}{\ln(a) \ln(b) \ln(c)}

Redistribute the factors on the left side as

xyz = \dfrac{\ln(b) + \ln(c)}{\ln(b)} \times \dfrac{\ln(a) + \ln(c)}{\ln(c)} \times \dfrac{\ln(a) + \ln(b)}{\ln(a)}

and simplify to

xyz = \left(1 + \dfrac{\ln(c)}{\ln(b)}\right) \left(1 + \dfrac{\ln(a)}{\ln(c)}\right) \left(1 + \dfrac{\ln(b)}{\ln(a)}\right)

Now expand the right side:

xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} \\\\ ~~~~~~~~~~~~+ \dfrac{\ln(c)\ln(a)}{\ln(b)\ln(c)} + \dfrac{\ln(c)\ln(b)}{\ln(b)\ln(a)} + \dfrac{\ln(a)\ln(b)}{\ln(c)\ln(a)} \\\\ ~~~~~~~~~~~~ + \dfrac{\ln(c)\ln(a)\ln(b)}{\ln(b)\ln(c)\ln(a)}

Simplify and rewrite using the logarithm properties mentioned earlier.

xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} + \dfrac{\ln(a)}{\ln(b)} + \dfrac{\ln(c)}{\ln(a)} + \dfrac{\ln(b)}{\ln(c)} + 1

xyz = 2 + \dfrac{\ln(c)+\ln(a)}{\ln(b)} + \dfrac{\ln(a)+\ln(b)}{\ln(c)} + \dfrac{\ln(b)+\ln(c)}{\ln(a)}

xyz = 2 + \dfrac{\ln(ac)}{\ln(b)} + \dfrac{\ln(ab)}{\ln(c)} + \dfrac{\ln(bc)}{\ln(a)}

xyz = 2 + \log_b(ac) + \log_c(ab) + \log_a(bc)

\implies \boxed{xyz = x + y + z + 2}

(C)

6 0
2 years ago
I need help please it’s for school
erma4kov [3.2K]

From Sweatcoin, London to the residence of Santa Claus is about 4,280 km away.

<h3>Where is the Santa Clause's residence? </h3>

The residence of Santa Clause is popularly known as the North Pole.

According to the above, we have to roughly calculate the distance from Sweatcoin in London to the North Pole. This distance is equivalent to about 4,280 km

Learn more about London in: brainly.com/question/7416097

7 0
2 years ago
PLEASE HELP!!!!
netineya [11]
1 quarter= .25
200 × .25= 50

1 dime= .10
.10×15= 15

1 penny= .01
.01× 300= 3

Answer: 50+15+3= $68
5 0
3 years ago
Read 2 more answers
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