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gavmur [86]
3 years ago
9

X + 3y = 2 -x + 2y = 3 Can somebody help me?

Mathematics
1 answer:
Alisiya [41]3 years ago
4 0
X = -1 ; y = 1

x + 3y = 2, isolate x by subtracting 3y from both sides. Now that x is alone (because x = -3y + 2) take -3y + 2 and plug it into the second equation.

-(-3y + 2) + 2y =3 ; multiply what’s in the parenthesis by -1. It now is 3y -2 + 2y =3, add the common variables ( 3y + 2y) and you now have 5y-2=3. Move the 2 to the other side by adding it to both sides, you now have 5y=5, divide both sides by 5 and y=1.

Take any equation and plug y in for 1 to get x.

For example, (in the second equation), -x+2(1)=3, multiply 2 by 1 and you’re left with -x+2=3. Subtract 2 on both sides and you have -x=1, now divide both sides by -1 and x=-1.

You can check your work by plugging in the x and/or y values into the equations
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What is the value of (4/5 a 1/3) x 5^2 + 5/6 expressed in simplest form
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Answer:

The choice C.

12 \frac{1}{2}

Step-by-step explanation:

( \frac{4}{5}  -  \frac{1}{3} ) \times  {5}^{2}   +  \frac{5}{6}  \\  \\ ( \frac{12}{15}  -  \frac{5}{15} ) \times 25 +  \frac{5}{6}  \\  \\ ( \frac{12 - 5}{15} ) \times 25 +  \frac{5}{6}  \\  \\ ( \frac{7}{15} ) \times 25 +  \frac{5}{6}  \\  \\  \frac{35}{3}  +  \frac{5}{6}  \\  \\  \frac{70}{6}  +  \frac{5}{6}  =  \frac{75}{6}  \\  \\  =  \frac{25}{2}  = 12 \frac{1}{2}

I hope I helped you^_^

8 0
3 years ago
(3x-7) (x+5) what is the value of x
pychu [463]

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Step-by-step explanation:

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7 0
3 years ago
Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
Gemiola [76]

Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

P(1\ girl) = 0.375

ii.

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

P(Atleast\ 2 \ girls) = 0.5

iii.

No\ girl = \{BBB\}

P(No\ girl) = 0.125

Step-by-step explanation:

Given

Children = 3

B = Boys

G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

P(1\ girl) = \frac{3}{8}

P(1\ girl) = 0.375

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

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