T(x, y) = (x - 5, y - 6) since you are trying to translate back to the original point and therefor should do the reverse set of translations
Answer:
We need to sketch the problem first.
Find the size of angle R.
One member travels a distance of 12km due north. Another team member heads 50degree east of north and travels a distance of 10km.
If se substute 50° of 180 we have
180-50=130°
The distance between the two team members is the missing side.
We know two sides and included angle, so we use the cosine rule.
A2+b2+c2-2bcCosA
= 102+122-(2x10x12xcos130°)
=100+144-(-147.08)
=100+144+147.08
=391.08
A==SQRT391.08
=19.775
19.7km
Step-by-step explanation:
transverse s at angle 135°
180° - 135° = 45°
Angle 2 is congruent to 45° because they're alternate exterior angles.
transverse t at angle 120°
180° - 120° = 60°
Angle 3 is congruent to 60° because they're alternate exterior angles.
One rule for exterior angles in triangles is that the exterior angle is equal to the sum of the two angles adjacent to the opposite angle of the exterior angle.
135° = angle 1 + 60°
angle 1 = 75°
120° = angle 1 + 45°
angle 1 = 75°
Therefore angle 1 is 75°,angle 2 is 45° and angle 3 is 60°
Answer: multiply the other side by 3 also
Step-by-step explanation:
What happens to one side must also happen to the other side. This is the only way to keep equations equal when changing constants and variables
