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gavmur [86]
2 years ago
9

X + 3y = 2 -x + 2y = 3 Can somebody help me?

Mathematics
1 answer:
Alisiya [41]2 years ago
4 0
X = -1 ; y = 1

x + 3y = 2, isolate x by subtracting 3y from both sides. Now that x is alone (because x = -3y + 2) take -3y + 2 and plug it into the second equation.

-(-3y + 2) + 2y =3 ; multiply what’s in the parenthesis by -1. It now is 3y -2 + 2y =3, add the common variables ( 3y + 2y) and you now have 5y-2=3. Move the 2 to the other side by adding it to both sides, you now have 5y=5, divide both sides by 5 and y=1.

Take any equation and plug y in for 1 to get x.

For example, (in the second equation), -x+2(1)=3, multiply 2 by 1 and you’re left with -x+2=3. Subtract 2 on both sides and you have -x=1, now divide both sides by -1 and x=-1.

You can check your work by plugging in the x and/or y values into the equations
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Find the area between the graph please
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The area of the region shown in the coordinate plane is 2.7823 units square.

<h3>What is integration?</h3>

It is defined as the mathematical calculation by which we can sum up all the smaller parts into a unit.

It is given that:

The graph of a function:

y = sinx

And a line segment passed through:

(0, 0) and (7π/6, -1/2)

First, find the equation of the line:

y = (-1/2)/(7π/6)[x]

y = (-3/7π)x

The area by definite integration:

\rm Area = \int\limits^{7\pi/6}_0 {[sinx - (-3/7\pi)x]} \, dx

\rm Area = \int\limits^{7\pi/6}_0 {[sinx +3x/7\pi ]} \, dx

After solving the above definite integral:

Area = 2.7823 units square

Thus, the area of the region shown in the coordinate plane is 2.7823 units square.

Learn more about integration here:

brainly.com/question/18125359

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