The type of current produced by a battery is direct current. C.
Answer:
The absorption lines will shift to the red (become longer).
This is because of the extra distance that a wavelength λ must travel between the vibrations of the source producing the spectrum.
Note that the Doppler effect of the source is slightly different for light waves than it is for sound waves because sound waves require a medium in which to travel while light waves do not require such a medium (example air).
The instant it was dropped, the ball had zero speed.
After falling for 1 second, its speed was 9.8 m/s straight down (gravity).
Its AVERAGE speed for that 1 second was (1/2) (0 + 9.8) = 4.9 m/s.
Falling for 1 second at an average speed of 4.9 m/s, is covered <em>4.9 meters</em>.
ANYTHING you drop does that, if air resistance doesn't hold it back.
There's really no way to calculate Molly's pulling force, because all
of the data given in the question only describes Samantha's situation.
The following solution assumes that Molly's wagon and dog are identical
in mass, acceleration, and frictionlessness to Samantha's:
Force = (mass) x (acceleration) =
(45 kg) x (0.85 m/s²) = <em>38.25 newtons</em>
(Assuming there's no friction anywhere in the wagon/ground system.)
Answer:
A. T₁ = 7.204 N
B. T₂ = 19.07 N
C. I = 0.011979 kg * m²
Explanation:
Given
m₁ = 2.02 kg , d = 0.120 m, m₂ = 3.06 kg, s = 1.17 m, t = 0.810s
The tension can be find using the conserved energy in each axis so:
∑Fₓ = T₁ = m₁ * a₁
∑Fy = m₂ * g - T₂ = m₂ * a₁
Now to find the acceleration can use the equation of Newton motion
s = v₁* t + ¹/₂ * a₁ * t ²
Solve to a'
a₁ = 2* s / t ² = 2 * 1.17 m / (0.810 s)²
a₁ = 3.566 m/s²
A).
T₁ = m₁ * a₁ = T₁ = 2.02 kg * 3.566 m/s²
T₁ = 7.204 N
B).
T₂ = m₂ *(g - a₁) = 3.06 kg *(9.8 - 3.566) m/s²
T₂ = 19.07 N
C).
Finally to find the moment of inertia use the equation
∑ T = (T₂ - T₁) * r = I * α
α = a₁ / r
I = (T₂ - T₁ )* r²/ a₁
I = ( 19.07 - 7.204)* (0.06 m)² / 3.566 m/s²
I = 0.011979 kg * m²