Answer:
(a) 693.12 torr
(b) 68.5 kilopascals
(c) 0.862 atmosphere
(d) 1.306 atmospheres
(e) 36.74 psi
Explanation:
(a) 0.912 atm = 0.912 atm × 760 torr/1 atm = 693.12 torr
(b) 0.685 bar = 0.685 bar × 100 kPa/1 bar = 68.5 kPa
(c) 655 mmHg = 655 mmHg × 1 atm/760 mmHg = 0.862 atm
(d) 1.323×10^5 Pa = 1.323×10^5 Pa × 1 atm/1.01325×10^5 Pa = 1.306 atm
(e) 2.50 atm = 2.50 atm × 14.696 psi/1 atm = 36.74 psi
Answer:
z = 0.8 (approx)
Explanation:
given,
Amplitude of 1 GHz incident wave in air = 20 V/m
Water has,
μr = 1
at 1 GHz, r = 80 and σ = 1 S/m.
depth of water when amplitude is down to 1 μV/m
Intrinsic impedance of air = 120 π Ω
Intrinsic impedance of water =
Using equation to solve the problem
E(z) is the amplitude under water at z depth
E_o is the amplitude of wave on the surface of water
z is the depth under water
now ,
taking ln both side
21.07 x z = 16.81
z = 0.797
z = 0.8 (approx)
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Answer:
A)take motion and induce a current
Explanation:
i hope it will be helpful
Answer: 4
Explanation:
The dependent variable is the temperature of the water.