Question

A 50-g chunk of a common metal at 80°C is placed into a calorimeter with 50 g of water at 50°C. At thermal equilibrium, which effect would be most likely?
Group of answer choices

The water will have changed temperature more than the metal.

The metal will have changed temperature more than the water.

The water will have gained more thermal energy than the metal lost.

The equilibrium temperature will be the average of 65°C.

Answer 1

Answer:

The metal will have changed temperature more than the water.

Explanation:

As we know that when two objects are mixed at different temperature then due to heat exchange between the two they both reach to same final temperature

This is known as thermal equilibrium

So here we have

Heat given by metal = heat absorbed by water

so we have

$m s_{metal} \Delta T_1 = m s_{water}\Delta T_2$

since mass of metal is same as that of water

so we have

$s_{metal} \Delta T_1 = s_{water}\Delta T_2$

so here we know that

$s_{water} > s_{metal}$

so temperature change in water must be smaller than that of metal