a. 46 m/s east
The jet here is moving with a uniform accelerated motion, so we can use the following suvat equation to find its velocity:
![v=u+at](https://tex.z-dn.net/?f=v%3Du%2Bat)
where
v is the velocity calculated at time t
u is the initial velocity
a is the acceleration
The jet in the problem has, taking east as positive direction:
u = +16 m/s is the initial velocity
is the acceleration
Substituting t = 10 s, we find the final velocity of the jet:
And since the result is positive, the direction is east.
b. 310 m
The displacement of the jet can be found using another suvat equation
where
s is the displacement
u is the initial velocity
a is the acceleration
t is the time
For the jet in this problem,
u = +16 m/s is the initial velocity
is the acceleration
t = 10 s is the time
Substituting into the equation,
![s=(16)(10)+\frac{1}{2}(3)(10)^2=310 m](https://tex.z-dn.net/?f=s%3D%2816%29%2810%29%2B%5Cfrac%7B1%7D%7B2%7D%283%29%2810%29%5E2%3D310%20m)
The initial temperature of the bar is 25. To get to the t temperature you need to add (t-25) degrees Celsius.
for 1 degree................... 7 Joules
y given degree........ p Joules
p=7y
In our case y=(t-25) .
h(t) = 7(t-25) which is the final answer.
1. Ask a question
2. Form a hypothesis
3. Experiment
4.Record data
5.Draw Conclusion
6. Share Results
Answer:
1/3 the distance from the fulcrum
Explanation:
On a balanced seesaw, the torques around the fulcrum calculated on one side and on another side must be equal. This means that:
![W_1 d_1 = W_2 d_2](https://tex.z-dn.net/?f=W_1%20d_1%20%3D%20W_2%20d_2)
where
W1 is the weight of the boy
d1 is its distance from the fulcrum
W2 is the weight of his partner
d2 is the distance of the partner from the fulcrum
In this problem, we know that the boy is three times as heavy as his partner, so
![W_1 = 3 W_2](https://tex.z-dn.net/?f=W_1%20%3D%203%20W_2)
If we substitute this into the equation, we find:
![(3 W_2) d_1 = W_2 d_2](https://tex.z-dn.net/?f=%283%20W_2%29%20d_1%20%3D%20W_2%20d_2)
and by simplifying:
![3 d_1 = d_2\\d_1 = \frac{1}{3}d_2](https://tex.z-dn.net/?f=3%20d_1%20%3D%20d_2%5C%5Cd_1%20%3D%20%5Cfrac%7B1%7D%7B3%7Dd_2)
which means that the boy sits at 1/3 the distance from the fulcrum.
- (spring constant) (new length of spring - original length of spring) = Force applied to spring.
that is
-kx=F
Did you only have how far the cart traveled? No mass or acceleration or speed or time taken?