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bonufazy [111]
3 years ago
5

What is the period of a wave with a speed of 20.0 m/s and a frequency of 10.0 Hz?

Physics
1 answer:
Delvig [45]3 years ago
4 0

<em>im confused hold on imma send you a link to the answer</em>Explanation:

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The answer is it's middle the nueculs

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3 years ago
If you told a policeman about a car traveling 44.704 m/s (100 mph) that was traveling in an eastward direction, you would be des
Tpy6a [65]

Answer:

Velocity

Explanation:

You would be describing the velocity of the car.

Velocity in physics is defined as Vector quantity that describes the displacement of an object with respect to the time it takes to attain it. Displacement is the addition of direction to the speed of an object. The displacement is noted in the question, "traveling eastward". While it is stated that the car travels at 44.704 m/s. Ordinarily, it would have been tagged speed, if not for the direction added to it which makes it velocity.

I hope you understand.

5 0
3 years ago
100 POINTS PLEASE HELP ASAP!!!!
elena-s [515]

Answer:

B

Explanation:

8 0
3 years ago
Read 2 more answers
Two horses, Thunder and Misty, are accelerating a wagon 1.3 m/s2. The force of friction is 75 N. Thunder is pulling with a force
just olya [345]

Answer:

1327 kg

Explanation:

So the net force exerted on the wagon would be the sum of forces from 2 horses subtracted by friction force

F = 1000 + 800 - 75 = 1725 N

This force results in an acceleration of a = 1.3 m/s2. We can use Newton's 2nd law to calculate the mass of the wagon

F = ma

m = F / a = 1725 / 1.3 \approx 1327 kg

3 0
4 years ago
Air at 80 kPa, 27°C, and 220 m/s enters a diffuser at a rate of 2.5 kg/s and leaves at 42°C. The exit area of the diffuser is
9966 [12]

Answer:

exit velocity = 62 m/s

exit pressure is 98.52332 kPa

Explanation:

given data

pressure p1 = 80 kPa

temperature t1 =  27°C = 300 K

velocity v1 = 220 m/s

temperature t2 =  42°C = 315K

area exit = 370 cm²

lose heat at a rate = 18 kJ/s

gas constant of air = 0.287 kPa·m^3/kg·K.

h1 = 300.19 kJ/kg

h2 = 315.27 kJ/kg

to find out

exit velocity and exit pressure

solution

first we apply here energy balance equation to find out outlet velocity

Einlet = Eoutlet

m(h1 + v1²/2)  = m (h2+v2²/2) +Q

m(v1²-v2²) /2  =  m (h2 -h1) +Q

v2² = v1² - 2Cp Δt - 2Q/m

here  Δt = h2 - h1 and put all value

v2² = 220² - 2(1.005)10³ (15) - 2(18)10³ /2.5

exit velocity = 62 m/s

so

now find outlet pressure that is

p2 = mRT / A2 v2

put value

p2 = 2.5 (287) 315 / (370 10^{-4} 62)

p2 = 98.52332 kPa

exit pressure is 98.52332 kPa

3 0
3 years ago
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