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zheka24 [161]
3 years ago
5

Using the completing-the-square method, find the vertex of the function f(x) =- 3x2 + 6x − 2 and indicate whether it is a minimu

m or a maximum and at what point.
Mathematics
1 answer:
svp [43]3 years ago
6 0
F(x) = -3x² + 6x - 2
First, we make the coefficient of x² equal to 1
f(x) = -3(x² + 2x - 2/3)

Now, we must make the form a² + 2ab + b²
b = 2x/2x
b = 1

f(x) = -3(x² + 2x + 1² - 1² - 2/3)
f(x) = -3(x² + 2x + 1 - 5/3)
f(x) = -3(x + 1)² - 5

The vertex is (-1 , -5)
And this is the maximum point because the coefficient of the squared term is negative.
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3/8 as a decimal is ??
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Answer:

0.375

Step-by-step explanation:

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3 years ago
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In circle A, ∠BAE ≅ ∠DAE. What is the length of BE? 14 units 17 units 27 units 34 units
zhannawk [14.2K]

Answer:

The length of BE is 27 units ⇒ 3rd answer

Step-by-step explanation:

In circle A:

∠BAE ≅ ∠DAE

Line segments A B, A E, and A D are radii

Lines are drawn from point B to point E and from point E to point D to form secants B E and E D

The length of B E is 3 x minus 24 and the length of E D is x + 10

We need to find the length of BE

∵ AB and AD are radii in circle A

∴ AB ≅ AD

In Δs EAB and EAD

∵ ∠BAE ≅ ∠DAE ⇒ given

∵ AB = AD ⇒ proved

∵ EA = EA ⇒ common side in the two triangles

- Two triangles have two corresponding sides equal and the

  including angles between them are equal, then the two

  triangles are congruent by SAS postulate of congruence

∴ Δ EAB ≅ Δ EAD ⇒ SAS postulate of congruence

By using the result of congruence

∴ EB ≅ ED

∵ EB = 3 x - 24

∵ ED = x + 10

- Equate the two expressions to find x

∴ 3 x - 24 = x + 10

- Add 24 to both sides

∴ 3 x = x + 34

- Subtract x from both sides

∴ 2 x = 34

- Divide both sides by 2

∴ x = 17

Substitute the value of x in the expression of the length of BE to find its length

∵ BE = 3 x - 24

∵ x = 17

∴ BE = 3(17) - 24

∴ BE = 51 - 24

∴ BE = 27

The length of BE is 27 units

3 0
3 years ago
Read 2 more answers
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The i in the denominator is missing in the second expression. It should be

\sin at=\dfrac{e^{iat}-e^{-iat}}{2i}

This follows from

e^{iat}=\cos at+i\sin at
e^{-iat}=\cos at-i\sin at
\implies e^{iat}-e^{-iat}=2i\sin at
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3 years ago
Which represents where f(x) = g(x)?
ANEK [815]

Answer:

f(2) = g(2) and f(0) = g(0)

Step-by-step explanation:

When x = x in f(x) and g(x), that means the two functions are equal.

7 0
3 years ago
Find the solution of the differential equation that satisfies the given initial condition. dy/dx = xe^y, y(0) = 0
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\dfrac{\mathrm dy}{\mathrm dx}=xe^y
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y(0)=0
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