step 1
Find the <span>average growth per year of the populations of rabbits farm A
</span><span>Over the first 2 years
for t=0
</span>numbers of rabbits=5 (is not exact)
for t=2
numbers of rabbits=40
average=[40-5]/2---------> 17.5
step 2
Find the average growth per year of the populations of rabbits farm B
Over the first 2 years
for t=0
numbers of rabbits=5 (is not exact)
for t=2
numbers of rabbits=30
average=[30-5]/2---------> 12.5
step 3
<span>Compare the average growth per year of the populations of rabbits on both farms
farm A=17.5
farm B=12.5
</span><span>the average rate of population growth of rabbits in farm A is greater than average rate of population growth of rabbits in farm B by about 5 rabbits per year.
therefore
the answer is the option C)
</span>the average rate of population growth of rabbits in farm A is greater than average rate of population growth of rabbits in farm B by about 6 rabbits per year.
Answer:
0.27
Step-by-step explanation:
If you subtract 1.07 from 1.34 it would equal 0.27.
Hello! :)
Let's use PEMDAS.
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction
(5-2) = 3 Do parenthesis.
7 × 3 = 21 Multiply with what we got after doing the parenthesis.
9 + 21 = 30 Add with what we had left.
30
Hope this helps!
ELITEDIPER
Answer:
Ayy thank you sa points bahaha