Question

How do I find out the exact solutions and approximate solutions?

Answer 1

Answer: Exact solutions are x = 2√2 and x = -2√2

Approximate solutions are x = 2.828 and x = - 2.828

The attachment shows a portion of the graph with this equation. The "zeros" are the solutions.

Step-by-step explanation: To get values for x, we need to isolate x

2x² -6 = 10  Add 6 to both sides and rewrite the equation as

2x² = 16  divide both sides by 2

x² = 8   Factor 8 as 4(2) so you can "pull out" a square.

To solve for x, take the square roots of both sides.

Remember that square roots are positive and negative values.

$\sqrt{x^2}$ = ± $\sqrt{4(2)}$

x = ± 2√2

x = 2√2 and  x = -2√2

We can use a calculator to get approximate values of x.

$2\sqrt{2}$ =  ±2.828427125

Round that to x =  2.828 or 2.83 AND x = - 2.828 for approximate values.