Answer:
The answer is "".
Step-by-step explanation:
Please find the complete question in the attached file.
We select a sample size n from the confidence interval with the mean
and default
, then the mean take seriously given as the straight line with a z score given by the confidence interval

Using formula:
The probability that perhaps the mean shells length of the sample is over 4.03 pounds is

Now, we utilize z to get the likelihood, and we use the Excel function for a more exact distribution
the required probability:

-5║4y-11║-3=12
-5║4y-11║-3 +3=12+3
- 5║4y-11║=15
-5/5║4y-11║=15/-5
║4y-11║=-3
4y-11=-3 -5║4y-11║-3=12
4y-11+11=-3+11 -5║4(2)-11║-3=12
4y=8 -5║-3║-3=12
4y/4=8/4 -5 (3)-3=12
y=2 -18≠12
4y-11=3 -5║4y-11║-3=12
4y-11+11=3+11 -5║4(7/2)-11║-3=12
4y=14 -5(3)-3=12
4y/4=14/4 -18≠ 12
y=7/2
No solutions
7/9% is not 7/9 of 1, it's 7/9 of 0.01.
So, it is 0.0078
Hope this helps!
Answer:
The volume of the box is 41.21 inches cube.
Step-by-step explanation:
Given,
Width of the box
inches
inches
Length of the box
inches
inches
Height of the box
inches
inches
The box is in cuboid form.
The volume of cuboid is given by (length × breadth × height ).
So,
volume of the box is
×
×

= 
inches cube
The volume of the box is 41.21 inches cube.