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3 years ago

I need help plz 99 points waiting for the person that answers the question

Mathematics

2 answers:

amid [387]3 years ago

4 0

Answer:

Step-by-step explanation:

This is from a website so you might have to rephrase it but Direct variation describes a simple relationship between two variables . We say y varies directly with x (or as x , in some textbooks) if:

y=kx

for some constant k , called the constant of variation or constant of proportionality . (Some textbooks describe direct variation by saying " y varies directly as x ", " y varies proportionally as x ", or " y is directly proportional to x .")

This means that as x increases, y increases and as x decreases, y decreases—and that the ratio between them always stays the same.

The graph of the direct variation equation is a straight line through the origin.

ddd [48]3 years ago

3 0

Any line that crosses through the origin is a direct variation:
y = kx y = kx y = kx
The graph you're looking at isn't a straight line. We can demonstrate this by demonstrating that the slopes of two pairs of points are not equal.
m = (4 - 0) / m = y/x (2 - 0)
m = 2 m = y/x m = (9 - 0) / (3 - 0) m = 3 m = 2 m = 3
As a result, this isn't a direct version.

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Aleksandr [31]

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3 years ago

Evaluate Dx / ^ 9-8x - x2^

Solnce55 [7]

It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for $\sqrt x$ .

In that case, you want to find the antiderivative,

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}$

Complete the square in the denominator:

$9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2$

Now substitute $x+4=5\sin y$ , so that $\mathrm dx=5\cos y\,\mathrm dy$ . Then

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy$

which simplifies to

$\displaystyle\int\frac{5\cos 
y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy$

Now, recall that $\sqrt{x^2}=|x|$ . But we want the substitution we made to be reversible, so that

$x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)$

which implies that $-\dfrac\pi2\le y\le\dfrac\pi2$ . (This is the range of the inverse sine function.)

Under these conditions, we have $\cos y\ge0$ , which lets us reduce $\sqrt{\cos^2y}=|\cos y|=\cos y$ . Finally,

$\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C$

and back-substituting to get this in terms of $x$ yields

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C$

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3 years ago

Which equation represents a linear function That is shown on the graph below?

jok3333 [9.3K]

The second one I believe because it’s basiclalu going up one half everytime to get to one

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2 years ago

Can someone please help me with math.

Umnica [9.8K]

Answer:

9) C. 35 + 0.12x = 44.36

10) B

11) A. 32

Step-by-step explanation:

44.36 is the TOTAL so the equations have to EQUAL it.

PER mile means it's a variable so it's 0.12x:

35 is a constant so there's no variable attached:

35 + 0.12x = 44.36

10)

B because you have to cancel the y values and to do that, you multiply the 1st equation by 3.

11)

0.1x + 0.25(46 - x) = 6.70

0.1x + 11.5 - 0.25x = 6.7

-0.15x = 6.7 - 11.5

-0.15x = -4.8

x = 32

5 0

3 years ago