PLS ANSWER ASAP!!!!!

A random sample of 20 recent weddings in a country yielded a mean wedding cost of $ 26,388.67. Assume that recent wedding costs

Makovka662 [10]

Answer:

a) 95% confidence interval for the meancost, μ, of all recent weddings in this country = (22,550.95, 30,226.40)

.The 95% confidence interval is from $22,550.95 to $30,226.40.

b) For the interpretation of the result, option D is correct.

We can be 95% confident that the mean cost, μ, of all recent weddings in this country is somewhere within the confidence interval.

c) Option B is correct.

The population mean may or may not lie in this interval, but we can be 95% confident that it does.

Step-by-step explanation:

Sample size = 20

Sample Mean = $26,388.67

Sample Standard deviation = $8200

Confidence Interval for the population mean is basically an interval of range of values where the true population mean can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample mean) ± (Margin of error)

Sample Mean = 26,388.67

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error of the mean)

Critical value will be obtained using the t-distribution. This is because there is no information provided for the population mean and standard deviation.

To find the critical value from the t-tables, we first find the degree of freedom and the significance level.

Degree of freedom = df = n - 1 = 20 - 1 = 19.

Significance level for 95% confidence interval

(100% - 95%)/2 = 2.5% = 0.025

t (0.025, 19) = 2.086 (from the t-tables)

Standard error of the mean = σₓ = (σ/√n)

σ = standard deviation of the sample = 8200

n = sample size = 20

σₓ = (8200/√20) = 1833.6

99% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 26,388.67 ± (2.093 × 1833.6)

CI = 26,388.67 ± 3,837.7248

99% CI = (22,550.9452, 30,226.3948)

99% Confidence interval = (22,550.95, 30,226.40)

a) 95% confidence interval for the meancost, μ, of all recent weddings in this country = (22,550.95, 30,226.40)

.The 95% confidence interval is from $22,550.95 to $30,226.40.

b) The interpretation of the confidence interval obtained, just as explained above is that we can be 95% confident that the mean cost, μ,of all recent weddings in this country is somewhere within the confidence interval

c) A further explanation would be that the population mean may or may not lie in this interval, but we can be 95% confident that it does.

Hope this Helps!!!

4 0

3 years ago

1. Work 8m + 5 = 6m + 17 Reason Given Statement

snow_tiger [21]

Answer:

m = 6

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Solve for b 117 63 27 160

Alisiya [41]

Answer:

27

Step-by-step explanation:

180-153=b

b=27

3 0

3 years ago

Read 2 more answers

Rob is twice Joshua's age. Nick is 5 years older than Joshua. The sum of all their ages is 45. How old is Nick?

MatroZZZ [7]

Given

Rob is twice Joshua's age

Nick is 5 years older than Joshua.

sum of all their ages is 45.

Find the age of nick.

To proof

As given

Rob is twice Joshua's age

let Joshua's age = x

than Rob age = 2x

Nick is 5 years older than Joshua.

Nick age = 5 + x

sum of all their ages is 45

than the equation becomes

Joshua's age + Rob age + Nick age = 45

put the value

x + 2x + 5 + x = 45

4x = 40

x = 10

Joshua's age = 10 year

than Rob age = 20 year

Nick age = 5 + 10

= 15year

Hence proved

6 0

3 years ago

BRAINLIEST ANSWER AND 98 POINTS!!!!

Alex73 [517]

Answer:

P (g1, g2) = P(g1) * P(g2) = 1/2 * 1/2 = 1/4

P (r1, r2) = P(r1) * P(r2) = 1/5 * 1/5 = 1/25

P ( b1, g1 or g1 b2) = 3/20 + 3/20 = 6/20 = 3/10

P ( b1, g1 or g1 b2) = 1/10 + 1/10 = 2/10 = 1/5

Step-by-step explanation:

How many marbles are there?

5 green, 3 black, and 2 red marbles = 10 marbles

P ( green marbles) = green/ total = 5/10 = 1/2

Then she puts it back, so there are still 10 marbles

P (2nd marble is green) = green/ total = 5/10 = 1/2

These are independent events ( since the marble is replaced)

P (g1, g2) = P(g1) * P(g2) = 1/2 * 1/2 = 1/4

P ( red marble) = red/ total = 2/10 = 1/5

Then she puts it back, so there are still 10 marbles

P (2nd marble is red) = red/ total = 2/10 = 1/5

These are independent events ( since the marble is replaced)

P (r1, r2) = P(r1) * P(r2) = 1/5 * 1/5 = 1/25

P ( black marble) = black/ total = 3/10

Then she puts it back, so there are still 10 marbles

P (2nd marble is green) = green/ total = 5/10 = 1/2

These are independent events ( since the marble is replaced)

P (b1, g2) = P(b1) * P(g2) = 3/10 * 1/2 = 3/20

This is if order matters, but I will assume order does not matter since the key word then is not there it just says and

If order doesn't matter, just that she has a black and green marble

The we multiply it by 2 because

P (b2, g1) = P(b2) * P(g1) = 1/2 * 3/10 = 3/20

We add the probabilities when it is or

P ( b1, g1 or g1 b2) = 3/20 + 3/20 = 6/20 = 3/10

P ( green marble) = green/ total = 5/10=1/2

Then she puts it back, so there are still 10 marbles

P (2nd marble is red) = red/ total = 2/10 = 1/5

These are independent events ( since the marble is replaced)

P (g1, r2) = P(g1) * P(r2) = 1/2 * 1/5 = 1/10

This is if order matters but I will assume order does not matter since the key word then is not there it just says and

If order doesn't matter, just that she has a green and red marble

The we multiply it by 2 because

P (r1, g2) = P(r1) * P(g2) = 1/5 * 1/2 = 1/10

We add the probabilities when it is or

P ( b1, g1 or g1 b2) = 1/10 + 1/10 = 2/10 = 1/5

3 0

3 years ago