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2 years ago

e="8 a b ^ { 2 } : 6 a ^ { 2 } b" alt="8 a b ^ { 2 } : 6 a ^ { 2 } b" align="absmiddle" class="latex-formula">
Express ratio in simplest form

Mathematics

1 answer:

g100num [7]2 years ago

4 0

$\boxed{\large{\bold{\blue{ANSWER~:) }}}}$

$8ab^{2}:6a^{2}b\\\\=\dfrac{8ab^{2}}{6a^2b}\\\\=\dfrac{2×4×a×b×b}{2×3×a×a×b}\\\\=\dfrac{4b}{3a}\\\\=4b:3a$

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Step-by-step explanation:

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3 years ago

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Answer:

Length:8 m

Width:3 m

Step-by-step explanation:

The complete question is

If the perimeter of a rectangle is 22 meters, and the perimeter of a right triangle is 12 meters (the sides of the triangle are half the length of the rectangle, the width of the rectangle, and the hypotenuse is 5 meters). How do you solve for L and W, the dimensions of the rectangle.

step 1

Perimeter of rectangle

we know that

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$P=2(L+W)$

we have

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$22=2(L+W)$

Simplify

$11=L+W$ -----> equation A

step 2

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The perimeter of triangle is equal to

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$12=\frac{L}{2}+W+5$

Multiply by 2 both sides

$24=L+2W+10$

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Solve the system of equations by graphing

Remember that the solution is the intersection point both graphs

using a graphing tool

The solution is the point (8,3)

see the attached figure

therefore

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Length:8 m

Width:3 m

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2 years ago

If the vertex of a parabola is (-4, 6) and another point on the curve is (-3, 14), what is the coefficient of the squared expres

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$\bf \qquad \textit{parabola vertex form}\\\\\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array}\qquad\qquad vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
vertex\ (-4,6)\qquad 
\begin{cases}
h=-4\\
k=6
\end{cases}\implies y=a(x-(-4))^2+6
\\\\\\
y=a(x+4)^2+6
\\\\\\
\textit{we also know that }
\begin{cases}
x=-3\\
y=14
\end{cases}\implies 14=a(-3+4)^2+6$

solve for "a"

8 0

3 years ago