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Sati [7]
3 years ago
6

Use the Daily Compounding chart in your book to answer the following question. Alana Geltner deposited $2,250 in a savings accou

nt that pays 5.5 percent interest compounded daily. How much interest did she earn after 130 days?
Mathematics
1 answer:
timama [110]3 years ago
7 0

Answer:

$2,369,136.10

Step-by-step explanation:

she earned $2,369,136.10 in interest after 130 days

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2r+2s=50<br> Please look at the picture
lidiya [134]

2r + 2s = 50

2r - s = 17

-----------subtract

3s = 33

s = 11

2r - s = 17

2r - 11 = 17

2r = 28

r = 14

so r = 14 and s = 11

answer is C. r = 14, s = 11

4 0
3 years ago
The fine schedule for overdue books at the county library is modeled by the values in the table.
Tasya [4]

Answer:

The answer would be B!

Step-by-step explanation:

In the chart if you divide the number of days over due to the cost of the fine, you get 5/2 every time. therefore, if y is the cost in cents and x is the days overdue, you would multiply x5/2 or y=5/2x, so your answer is B (y=5/2x).  

hoped this helped :D

3 0
3 years ago
Read 2 more answers
Kayla and Camille, both teachers, are adding books to their class libraries. Kayla’s classroom started out with a collection of
Airida [17]
34
because, 34 = 14 + (10 x 2)
and 34 = 24 + (10 x 1)
4 0
4 years ago
Find a polynomial function f(n) such that f(1), f(2), ... , f(8) is the following sequence.
Irina18 [472]
Observing there is a difference of +8 between each f(x).
The slope of this sequence is 8.(y2-y1)/(x2-x1)
Using the point slope equation,
y-y1 = m(x-x1) yields

y = 8x -4 as the answer.
5 0
4 years ago
A cardboard box without a lid is to have a volume of 19,652 cm3. Find the dimensions that minimize the amount of cardboard used.
Effectus [21]

Answer:

The dimension of the cardboard is 34 cm by 34 cm by 17 cm.

Step-by-step explanation:

Let the dimension of the cardboard box be x cm by y cm by z cm.

The surface area of the cardboard box without lid is

f(x,y,z)= xy+2xz+2yz.....(1)

Given that the volume of the cardboard is 19,652 cm³.

Therefore xyz =19,652

\Rightarrow z=\frac{19652}{xy}......(2)

putting the value of z in the equation (1)

f(x,y)=xy+2x(\frac{19652}{xy})+2y(\frac{19652}{xy})

\Rightarrow f(x,y)=xy+\frac{39304}{y})+\frac{39304}{x}

The partial derivatives are

f_x=y-\frac{39304}{x^2}

f_y=x-\frac{39304}{y^2}

To find the dimension of the box set the partial derivatives f_x=0 and f_y=0.Therefore y-\frac{39304}{x^2}=0

\Rightarrow y=\frac{39304}{x^2}.......(3)

and   x-\frac{39304}{y^2}=0

\Rightarrow x=\frac{39304}{y^2}.......(4)

Now putting the x in equation (3)

y =\frac {39304}{(\frac{39304}{y^2})^2}

\Rightarrow y=\frac{y^4}{39304}

\Rightarrow y^3= 39304

⇒y=34 cm

Then \Rightarrow x=\frac{39304}{34^2} =34 cm.

Putting the value of x and y in the equation (2)

z=\frac{19652}{34 \times 24}

  =17 cm.

The dimension of the cardboard is 34 cm by 34 cm by 17 cm.

4 0
3 years ago
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