Answer:
∠BKM= ∠ABK
Therefore AB ║KM (∵ ∠BKM= ∠ABK and lies between AB and KM and BK is the transversal line)
m∠MBK ≅ m∠BKM (Angles opposite to equal side of ΔBMK are equal)
Step-by-step explanation:
Given: BK is an angle bisector of Δ ABC. and line KM intersect BC such that, BM = MK
TO prove: KM ║AB
Now, As given in figure 1,
In Δ ABC, ∠ABK = ∠KBC (∵ BK is angle bisector)
Now in Δ BMK, ∠MBK = ∠BKM (∵ BM = MK and angles opposite to equal sides of a triangle are equal.)
Now ∵ ∠MBK = ∠BKM
and ∠ABK = ∠KBM
∴ ∠BKM= ∠ABK
Therefore AB ║KM (∵ ∠BKM= ∠ABK and BK is the transversal line)
Hence proved.
To solve this question we will use two important formulas.
The first formula involves the calculation of the decay constant,
which is to be found as:

where
is the half life of Pb-210 which is given to be 22 years in the question.
Thus, 
Now, we will use the second formula which is called the function of decay formula and is given as:

where
percentage of Pb-210 remaining in the bone at present, which in our case is 67% or 0.67
percentage of Pb-210 to start with, which is always 100% or 1.
Plugging in all these values in the decay formula we are supposed to find the time,
.

Taking natural log on both sides we get:



years
Therefore the bone fragment is about 12.71 years old.
Earthquakes and fault lines
Factor the numerator and denominator...
(n^4-5n^2-6n^2+30)/(n^4-2n^2-5n^2+10)
[n^2(n^2-5)-6(n^2-5)]/[n^2(n^2-2)-5(n^2-2)]
[(n^2-5)(n^2-6)]/[(n^2-5)(n^2-2)] notice the (n^2-5)s cancel out
(n^2-6)/(n^2-2)
We could further factor this because each is a difference of squares to:
[(n+√6)(n-√6)]/[(n+√2)(n-√2)