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NNADVOKAT [17]
3 years ago
13

How many moles of NaCl are present in .05 L of 2.3 M NaCl solution?

Chemistry
2 answers:
alexandr1967 [171]3 years ago
6 0
N = 1.15 mol so choose dat one :) have a good day <3
ipn [44]3 years ago
5 0

Answer:

n = 1.15 mol

Explanation:

C = n/ V

n= C×V

n= 2.3× 0.5

n = 1.15 mol

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