What does the following code do?

Bad White [126]

Write about art bc thags always so cool

4 0

3 years ago

What two devices in a computer should be considered "black boxes," and should never be opened due to risks involving charged cap

NNADVOKAT [17]

The two devices in a computer that should be considered "black boxes," and should never be opened due to risks involving charged capacitors are MONITOR and POWER SUPPLY.

Explanation:

Physical contact or close proximity to the open power supply caused a discharge from the capacitor that resulted in an electric shock. Capacitors can discharge current even when not energized because they hold a charge for some time after the power is turned off.
To do harm to your body, the voltage across the capacitor's terminals must be high enough to cause a harmful effect on you. There are no hard rules for at what voltage things become harmful, but a common 'rule of thumb' is that DC up to 48 Volt is considered low voltage. So a capacitor charged to a voltage below 48 V is fairly safe.
A charged capacitor can be very dangerous, so it's important that you avoid coming into contact with the terminals at all times.

3 0

3 years ago

"When analyzing the IDS logs, the system administrator notices connections from outside of the LAN have been sending packets whe

lakkis [162]

This is false negative. To be marked for alert.

<u>Explanation:</u>

The network administrator or network engineer when he or she is analyzing IDS logs and founded the ip address is same on source and destination both in outside side.

So the either TCPIP address has to change to be scanned across the network. Since same IP address is same pinging rate will high and pinging the same workstation or desktop or laptop.

Alert will not generate because both tcpip address same and if pinging is success. Ids logs generates based true negative, true positive and false positive will not generate any alert.

5 0

4 years ago

Protocol 2 - Check for Errors

Lapatulllka [165]

Please note that the Problem to be solved from Protocol 1 is not provided hence the general answers. To construct and send, open a network environment a single multi-packet message, simply click "Add Packet" and then click "Send at Once".

<h3>How will the receiver know the order of the packets or if any are missing?</h3>

If the text or message sent does not make any reading sense, or if certain words are jumbled and out of place, then it is clear that something is wrong.

If the messages arrive in a coherent fashion, then the packet was fully received.

<h3>How will the receiver request missed packets and what will the sender do in response?</h3>

Where the users are familiar with the Transmission Control Protocol, lost packets can be detected when there is a timeout. Lost packets are referred to as Dropped packets.

Learn more about Packets at:
brainly.com/question/17777733

7 0

2 years ago

Program 7 - Circle You write ALL the code, then run it - Produce the correct output. Turn in code and screen print of successful

fgiga [73]

Answer:

Here is the Circle class:

public class Circle { // class definition

private int radius; // private data member of type int of class Circle named radius that stores the value of radius

public Circle(int r) { // parameterized constructor of class Circle that takes radius as argument

radius = r; } // sets value of radius as r

public int getRadius() { // accessor method to get the value of radius

return radius; } // returns the current value of radius

public int Diameter() { // method to compute diameter of a circle

return radius * 2; } // multiply radius value by 2 to compute diameter of Circle

public double Area() { // method to compute area of a circle

return Math.PI * Math.pow(radius, 2); } //the formula of area is

π x radius² where value of π is get using Math.PI

public double Circumference() { // // method to compute circumference of a circle

return 2* Math.PI * radius; } } //the formula of circumference is

2 x π x radius where value of π is get using Math.PI

Explanation:

Here is the Main class:

import java.util.Scanner; //to accept input from user

public class Main { //definition of Main class

public static void main(String[] args) { //start of main method

Scanner scanner = new Scanner (System.in); //creates Scanner object to take input from user

System.out.println("Enter radius: "); //prompts user to enter radius

int r = scanner.nextInt(); //reads the value of radius from user

Circle c = new Circle(r); // calls Constructor of Circle passing r as argument to it using the object c of class Circle

if(c.getRadius()<=0){ //calls getRadius method to get current value of radius using objec and checks if this value (input value of r ) is less than or equal to 0

System.out.println("Error!"); } //when above if condition evaluates to true then print this Error! message

else { //if the value of radius is greater than 0

System.out.println("the radius of this Circle is: " +c.getRadius()); //calls getRadius method to return current value of r (input value by user)

System.out.println("the diameter of this Circle is: " + c.Diameter()); //calls Diameter method to compute the diameter of Circle and display the result on output screen

System.out.printf("the circumference of this Circle is: %.2f", c.Circumference()); //calls Circumference method to compute the Circumference of Circle and display the result on output screen

System.out.println(); //prints a line

System.out.printf("the Area of this Circle is: %.2f", c.Area()); } } }

//calls Area method to compute the Area of Circle and display the result on output screen

The program and its output is attached.

7 0

3 years ago