The question is incomplete. Here is the complete question.
Find the measurements (the lenght L and the width W) of an inscribed rectangle under the line y = -
x + 3 with the 1st quadrant of the x & y coordinate system such that the area is maximum. Also, find that maximum area. To get full credit, you must draw the picture of the problem and label the length and the width in terms of x and y.
Answer: L = 1; W = 9/4; A = 2.25;
Step-by-step explanation: The rectangle is under a straight line. Area of a rectangle is given by A = L*W. To determine the maximum area:
A = x.y
A = x(-
)
A = -
To maximize, we have to differentiate the equation:
= 
(-)
= -3x + 3
The critical point is:
= 0
-3x + 3 = 0
x = 1
Substituing:
y = -x + 3
y = -.1 + 3
y = 9/4
So, the measurements are x = L = 1 and y = W = 9/4
The maximum area is:
A = 1 . 9/4
A = 9/4
A = 2.25
It has 3 zeros, because its a polynomial of degree 3.
Answer:
<h2>FALSE</h2>
Step-by-step explanation:
<h3>to understand this</h3><h3>you need to know about:</h3>
<h3>tips and formulas:</h3>
order of PEMDAS
- parentheses
- exponent
- multiplication or
- division
- addition
- subtraction
<h3>let's solve:</h3><h2><u>L.</u><u>H.S</u><u>=</u></h2>
- <u>
</u> - <u>
</u>
<h2><u>≠R.H.S</u></h2>
therefore
<h3>the equality is false</h3>
Answer:
38.5cm³
Step-by-step explanation:
1ml = 1cm³
38.5ml = 38.5cm³
