Area of the rectangular mat = 12 x 4 = 48 in²
Area of the 3 circles = 3( πr²) = 3(3.14 x 2²) = 37.68 in²
P(landing in a circle) = 37.68/48 = 157/200 = 0.79 (nearest hundredth)
Answer: The probability of landing in one of the circles is 0.79.
Answer:
C.
Step-by-step explanation:
First, lets find the y-intercept. The y-intercept where the line passes through the y-axis. In this case, it is -3.
Now, to find the slope, lets find the next non-decimal point(that way it is easier on us). That would be (1,-1). Now, to get to this point from the y-intercept, we have to go left 1 unit, and up 2 units. So, the change in y over change in x = 2/1 or 2. Now, using this information, we can form the equation:
y = 2x + -3. or y = 2x - 3.
It is a diagonal line that intersects the y-axis at y=5 and it intersects the x-axis at x=-4. The slope of the graph is 5/4.
<span>What is the corresponding value at the given point?
x = -15
</span>
C. 7=-2
If the choices are the following:
The legs are congruent.
The base angles are congruent.
The bases are | |.
<span>The diagonals are congruent.
Then , to prove </span>ACD ≅ BDC by SSS I would use The base angles are congruent.
<span>This is sufficient to prove the triangles are congruent.</span>
