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Ghella [55]
3 years ago
9

Is this statement about equivalent expressions true? (2 + 5) + 8 = 2 + (5 + 8)

Mathematics
1 answer:
alexdok [17]3 years ago
6 0
Yes

(2+5)+8=2+(5+8)
7+8=2+13
15=15
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Write down the nth term of this sequence 2,7,12,17,22
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There is a pattern. Each number is added by 5. So take 22 and add 5 to get 27. Just repeat until you find your answer, which would be 42.
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Given the function g(x)=−2x−8, evaluate g(0).
Vera_Pavlovna [14]

Answer:

g(0) = -8

Step-by-step explanation:

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3 years ago
The region in the first quadrant bounded by the x-axis, the line x = ln(π), and the curve y = sin(e^x) is rotated about the x-ax
charle [14.2K]
First, it would be good to know that the area bounded by the curve and the x-axis is convergent to begin with.

\displaystyle\int_{-\infty}^{\ln\pi}\sin(e^x)\,\mathrm dx

Let u=e^x, so that \mathrm dx=\dfrac{\mathrm du}u, and the integral is equivalent to

\displaystyle\int_{u=0}^{u=\pi}\frac{\sin u}u\,\mathrm du

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Now, to compute the volume. Via the disk method, we have a volume given by the integral

\displaystyle\pi\int_{-\infty}^{\ln\pi}\sin^2(e^x)\,\mathrm dx

By the same substitution as before, we can write this as

\displaystyle\pi\int_0^\pi\frac{\sin^2u}u\,\mathrm du

The half-angle identity for sine allows us to rewrite as

\displaystyle\pi\int_0^\pi\frac{1-\cos2u}{2u}\,\mathrm du

and replacing v=2u, \dfrac{\mathrm dv}2=\mathrm du, we have

\displaystyle\frac\pi2\int_0^{2\pi}\frac{1-\cos v}v\,\mathrm dv

Like the previous, this require a special function in order to express it in a closed form. You would find that its value is

\dfrac\pi2(\gamma-\mbox{Ci}(2\pi)+\ln(2\pi))

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5 0
3 years ago
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