Is the following relation a function? Yes No

6r-16 _ r r=4 What is the answer?

Setler [38]

The answer is 8
6(4)-16=8 :)

3 0

3 years ago

Jessie says to round 736,400 to the nearest ten thousand ,he will round to 770,000. is he right? explain.

djverab [1.8K]

no because if your rounding 736,400 it will be 740,000 if its 4 or less you let it rest if its 5 or more it rises

3 0

3 years ago

John makes a commission of 2% when he sells a house. How much will John make in commission if he sells a house for $300,000?

Anuta_ua [19.1K]

Answer: As a result of his company being able to sell a house of $300,000, John will earn a commission of $6,000.

When John sells a house, he gets a commission of 2% out of the selling price of that house.

If a house sells for $300,000 therefore, John will earn a commission of:

= Selling price of house x John's commission

= 300,000 x 2%

= $6,000

In conclusion, John will make a commission of $6,000.

Step-by-step explanation:

4 0

2 years ago

An oil refinery is located on the north bank of a straight river that is 2 km wide. A pipeline is to be constructed from the ref

hichkok12 [17]

Answer:

P is exactly 3km east from the oil refinery.

Step-by-step explanation:

Let's d be the distance in km from the oil refinery to point P. So the horizontal distance from P to the storage is 3 - d and the vertical distance is 2. Hence the diagonal distance is:

$\sqrt{(3 - d)^2 + 2^2} = \sqrt{(3 - d)^2 + 4}$

So the cost of laying pipe under water with this distance is

$800000\sqrt{(3 - d)^2 + 4}$

And the cost of laying pipe over land from the refinery to point P is 400000d. Hence the total cost:

$800000\sqrt{(3 - d)^2 + 4} + 400000d$

We can find the minimum value of this by taking the 1st derivative and set it to 0

$800000\frac{2*0.5*(3-d)(-1)}{\sqrt{(3 - d)^2 + 4}} + 400000 = 0$

We can move the first term over to the right hand side and divide both sides by 400000

$1 = 2\frac{3 - d}{\sqrt{(3 - d)^2 + 4}}$

$\sqrt{(3 - d)^2 + 4} = 6 - 2d$

From here we can square up both sides

$(3 - d)^2 + 4 = (6 - 2d)^2$

$9 - 6d + d^2 + 4 = 36 - 24d + 4d^2$

$3d^2-18d+27 = 0$

$d^2 - 6d + 9 = 0$

$(d - 3)^2 = 0$

$d -3 = 0$

d = 3

So the cost of pipeline is minimum when P is exactly 3km east from the oil refinery.

3 0

3 years ago

Find the equation of the line passing through the point (2,−4) that is parallel to the line y=3x+2

Naily [24]

Hey there! :)

Line passes through (2, -4) & parallel to y = 3x+ 2

Let's start off by identifying what our slope is. In the slope-intercept form y=mx+b, we know that "m" is our slope. "M" is simply a place mat so if we look at our given line, the "m" value is 3. Therefore, our slope is 3.

We should also note that we're looking for a line that's parallel to the given one. This means that our new line has the same slope as our given line. Therefore, our slope for our new line will be 3.

Now, we use point-slope form ( y-y₁=m(x-x₁) ) to complete our task of finding a line that passes through (2, -4) with a slope of 3.

y-y₁=m(x-x₁)

Let's start by plugging in 3 for m (our slope), 2 for x1 and -4 for y1.

y - (-4) = 3(x - 2)

Simplify.

y + 4 = 3x - 6

Simplify by subtracting 4 from both sides.

y = 3x - 10

~Hope I helped!~

8 0

3 years ago