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PolarNik [594]
3 years ago
10

When are scalars used?

Physics
1 answer:
Shkiper50 [21]3 years ago
7 0
When you have to wait some
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The specific heat(c) of copper is 0.39 J/g °C. What is the temperature
horsena [70]

Answer:12.8°c

Explanation:

specific heat capacity of copper(c)=0.39J*g°c

Mass(m)=20grams

Quantity of heat(Q)=100joules

Temperature rise(@)=?

@=Q/(mxc)

@=100/(20x0.39)

@=100/7.8

@=12.8°c

8 0
3 years ago
What is the kinetic energy of a an 80kg football player running at 8 m/s?
Ugo [173]
In the question it is already given that the football player is 80 kg.
Then the mass of the football player = 80 kg
Velocity at which the football player is running = 8 m/s
<span>Kinetic Energy = 0.5 • mass • square of velocity
Now we have to put the known data in this equation to find the actual velocity of the footballer.
</span> <span></span>So
Kinetic Energy of the footballer = 0.5 * 80 * (8 * 8)
                                                 = 0.5 * 80 * 64
                                                 = 2560
So the Kinetic energy of the footballer is 2560 joules


4 0
3 years ago
Determine the accelerations that result when a 45 N net force is applied to 3kg object
svp [43]

Answer:

acceleration is 18

Explanation:

45N/3kg=18

4 0
3 years ago
Read 2 more answers
You are a traffic accident investigator. You have arrived at the scene of an accident. Two cars of equal mass (1,000 kg each) we
kumpel [21]
6. Is 50 m/s that’s the answer
4 0
3 years ago
Compare the magnitude of the electromagnetic and gravitational force between two electrons separated by a distance of 2.00 m. As
Lesechka [4]
First you need to know about two laws, which are:
1) Coulomb's law
2) Newton's law of gravitation

1.
According to Coulomb's law, Electric force between TWO charges is:
F_{e} =  \frac{k*q_{1}*q_{2}}{r^{2}} -- (A)

Where, k = 1/(4*π*epsilon_not) = 9 * 10^{9} \frac{Nm^{2}}{C^{2}}

Both q_{1} and q_{2} = -1.61 x 10^{-19} C
r = Distance between the two charges = 2.00m

Plug-in the above values in (A), you would get:

F_{e} = (9 * 10^{9} ) (1.61 * 10^{-19}  * 1.61 * 10^{-19}) / (2*2)  

F_{e} = 5.83* 10^{-29} N

2.
According to Newton's law of gravitation:
F_{g} =  \frac{Gm_{1}m_{2}}{r^{2}} -- (B)

Where G = Gravitational constant = 6.674 * 10^{-11} m^{2} kg^{-1}s^{-2}

m1 = m2 = Mass of the electron = 9.11 * 10^{-31} kg
r = 2.0 m

Plug-in the above values in (B), you would get:

F_{g} = (6.674 * 10^{-11}) ( 9.11 * 10^{-31}  *  9.11 * 10^{-31}}[/tex]) / (2*2)  

F_{e} = 5.83* 10^{-29} N

F_{e} = 1.38 * 10^{-71} N

Now do Fe over Fg, you would get:
\frac{F_{e}}{F{g}}  = 4.23 * 10^{42}

Ans: So the blanks are:
1) 5.82
2) 1.38
3) 4.23

-i
6 1
3 years ago
Read 2 more answers
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