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Aleksandr [31]
3 years ago
9

How many steps in glycolysis have atp as a substrate or product?

Physics
1 answer:
Lana71 [14]3 years ago
5 0

Answer:

4

Explanation:

1. Phosphorylation of Glucose

2. Production of Fructose-6 Phosphate

3. Production of Fructose 1, 6-Diphosphate

4. Splitting of Fructose 1, 6-Diphosphate

5. Interconversion of the Two Sugars

6. Formation of NADH and 1,3-Diphoshoglyceric acid

7. Production of ATP and 3-Phosphoglyceric Acid

8. Relocation of Phosphorus Atom

9. Removal of Water

10. Creation of Pyruvic Acid and ATP

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Answer:

3.5 seconds of flight time; 13.9 m from the base of the cliff

Explanation:

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ball A of mass 5.0 kg moving at 20 meters per second collides with ball B of unknown mass moving at 10. meters per second in the
antiseptic1488 [7]

Answer:The mass of ball B is 10 kg.

Explanation;

Mass of ball A = M_A=5 kg

Velocity of the ball A before collision:U_A=20 m/s

Velocity of ball A after collision=V_A=10 m/s

Mass of ball B= M_B

Velocity of the ball B before collision:U_B=10 m/s

Velocity of ball B after collision=V_B=15 m/s

M_AV_A+M_BV_B=M_AU_A+M_BU_B

5 kg\times 10 m/s+M_B\times 15=5 kg\times 20m/s+M_B\times 10m/s

M_B=10kg

The mass of ball B is 10 kg.

8 0
2 years ago
Large power plants in the United States currently use what generators.
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3 0
3 years ago
Lloyd is standing on a scaffolding 12 meters above the ground to clean the windows of a tall building. His bucket, which has a m
Sever21 [200]

Answer:

U₂ = 20 J

KE₂ = 40 J

v= 12.64 m/s

Explanation:  

Given that

H= 12 m

m = 0.5 kg

h= 4 m

The potential energy at position 1

U₁ = m g H

U₁ = 0.5 x 10 x 12        ( take g= 10 m/s²)

U₁ = 60 J

The potential energy at position 2

U₂ = m g h

U ₂= 0.5 x 10 x 4        ( take g= 10 m/s²)

U₂ = 20 J

The kinetic energy at position 1

KE= 0

The kinetic energy at position 2

KE= 1/2 m V²

From energy conservation

U₁+KE₁=U₂+KE₂

By putting the values

60 - 20 = KE₂

KE₂ = 40 J

lets take final velocity is v m/s

KE₂= 1/2 m v²

By putting the values

40 = 1/2 x 0.5 x v²

160 = v²

v= 12.64 m/s

3 0
3 years ago
Read 2 more answers
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