Answer rain gauge measures rain shadow units millimetres
Answer:
fr = ½ m v₀²/x
Explanation:
This exercise the body must be on a ramp so that a component of the weight is counteracted by the friction force.
The best way to solve this exercise is to use the energy work theorem
W = ΔK
Where work is defined as the product of force by distance
W = fr x cos 180
The angle is because the friction force opposes the movement
Δk =
–K₀
ΔK = 0 - ½ m v₀²
We substitute
- fr x = - ½ m v₀²
fr = ½ m v₀²/x
Answer:
The amount of mass that needs to be converted to release that amount of energy is 
Explanation:
From Albert Einstein's Energy equation, we can understand that mass can get converted to energy, using the formula

where
= change in mass
c = speed of light = 
Making m the subject of the formula, we can find the change in mass to be

There fore, the amount of mass that needs to be converted to release that amount of energy is 1.122 X 10 ^-7 kg
Because it can pollute the air and cause wild life to eat stuff that has been contimanted by the air