Answer:
The velocity of jet in still air is 
and velocity of wind is
.
Step-by-step explanation:
Let x be the rate of the jet in still air and y be the rate of the wind.
Given:
Velocity against wind, a jet travels 2160 miles in 3 hours.
Velocity against wind 
Flying with the wind, same jet travels 6000 miles in 6 hours.
Flying with the wind 
As such its velocity against wind is 
and with wind is
therefore
------------(1)
---------------(2)
Adding equation 1 and 2.
Put x value in equation 2
Hence velocity of jet in still air is and velocity of wind is
.
It would be e, because it went down 10 instead of 5
For y=4 draw a horizontal line through the y-axis at point (0,4). Y-axis is the vertical.
For x=-3 draw a vertical line through the x-axis at point (-3,0). X-axis is the horizontal.
The circle with center O has two chords AC and EF which are of same length 9.07.
OD and OB are the two perpendiculars drawn from the center O to the two chords AC and EF .It represents the distance of the chords from the centre.
The circle theorem states: congruent chords are equidistant from the center.
OD is congruent to OB.
Option A is the right answer.
Answer:
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Step-by-step explanation:
