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Alex787 [66]
3 years ago
9

write the expressions for when you translate the graph of y = |x+2| a) one unit up b) one unit down c) one unit to the left d) o

ne unit to the right
Mathematics
1 answer:
irina1246 [14]3 years ago
6 0

Hello!

This question is about which values you are changing when you are transforming an equation.

Let's go through the parent function for an absolute value equation and its various transformations.

y=a|b(x-c)|+d

Since we are only looking at horizontal and vertical transformations, we only need to worry about the c and d values.

The c value of a function determines a function's horizontal position, and the d value of a function determines a function's vertical position.

One thing to note here is that the c value is being subtracted from the x value, meaning that if the function is being transformed to the right, you would actually be subtracting that value, while the d value behaves like a normal value, if it is being added, the function is transformed up, and vice versa.

Now that we know this, let's write each expression.

a) y=|x+2|+1

b) y=|x+2|-1

c) y=|x+3|

d) y=|x+1|

Hope this helps!

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Pilar says that two linear systems below have the same solution. (see picture) Is she correct? Explain.
wariber [46]
The first set:

3x + 2y = 2  ---1)
5x + 4y = 6  ---2)

From 1), multiply all by 2, 6x + 4y = 4  ---3)

3) - 2),

6x + 4y - (5x + 4y) = 6 - 4
6x + 4y - 5x - 4y = 2
x = 2

Sub in x = 2 into 1),

3(2) + 2y = 2
2y = -4
y = -2

(2 , -2)


The second set:

3x + 2y = 2  ---1)
11x + 8y = 10  ---2)

From 1), multiply all by 4, 12x + 8y = 8 ---3)

3) - 2),

12x + 8y - (11x + 8y) = 8 - 10
12x + 8y - 11x - 8y = -2
x = -2

From this x value alone, we can tell that these two linear systems do NOT have the same solution as they meet at different coordinates.

Hope this helped! Ask me if there's any working from here that you don't understand! :)

5 0
3 years ago
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What is the answer to 8x^3+125 by factoring the perfect cube?
expeople1 [14]

Answer:

\large\boxed{8x^3+125=(2x+5)(4x^2-10x+25)}

Step-by-step explanation:

8x^3+125=2^3x^3+5^3=(2x)^3+5^3\\\\\text{use}\ a^3+b^3=(a+b)(a^2-ab+b^2)\\\\=(2x+5)((2x)^2-(2x)(5)+5^2)\\\\=(2x+5)(4x^2-10x+25)

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Nat2105 [25]
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Question : In the given figure , ∆ APB and ∆ AQC are equilateral triangles. Prove that PC = BQ.
lorasvet [3.4K]

Answer:

See Below.

Step-by-step explanation:

We are given that ΔAPB and ΔAQC are equilateral triangles.

And we want to prove that PC = BQ.

Since ΔAPB and ΔAQC are equilateral triangles, this means that:

PA\cong AB\cong BP\text{ and } QA\cong AC\cong CQ

Likewise:

\angle P\cong \angle PAB\cong \angle ABP\cong Q\cong \angle QAC\cong\angle ACQ

Since they all measure 60°.

Note that ∠PAC is the addition of the angles ∠PAB and ∠BAC. So:

m\angle PAC=m\angle PAB+m\angle BAC

Likewise:

m\angle QAB=m\angle QAC+m\angle BAC

Since ∠QAC ≅ ∠PAB:

m\angle PAC=m\angle QAC+m\angle BAC

And by substitution:

m\angle PAC=m\angle QAB

Thus:

\angle PAC\cong \angle QAB

Then by SAS Congruence:

\Delta PAC\cong \Delta BAQ

And by CPCTC:

PC\cong BQ

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Mashutka [201]

Answer:

B. A teacher compares the pre-test and post-test scores of students

Step-by-step explanation:

the answer is true, because it is a good example to compare the tests between students, we know that a matching pair design is a random model and is used when the experiment allows grouping subjects in pairs based on a variable and each pair will receive randomly a different handling, the answer A is not true because in the example all students are uniformly averaged and the variable is not correlated with subgroups, option c is incorrect because the variable was not randomized and generates classification bias and the option d is incorrect because the teacher compares a small sample as her class with a score of a total sample, but does not intervene on her students when selecting the corresponding group

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