Answer:
A.
B.
C. ΔK
Explanation:
From the exercise we know that the car and the truck are traveling eastward. I'm going to name the car 1 and the truck 2
A. Since the two vehicles become entangled the final mass is:
From linear momentum we got that:
B. The change in velocity of both vehicles are:
For the car
For the truck
C. The change in kinetic energy is:
ΔK=
ΔK=
ΔK
If the echo is detected 2 seconds after the ping is transmitted,
then the sound has traveled
(2 sec) x (1533 meter/sec) = 3,066 meters.
But the sound had to travel down from the boat to the bottom, then
get reflected, then travel up from the bottom to the boat. So the
sound actually traveled a distance equal to double the depth.
The depth is (1/2) (3,066 meters) = 1,533 meters .
(about 5,030 feet)
Answer: 1.653 × 10⁴ N/C
Explanation: Given Q= 3.6× 10^-6
we assume there is a charge q placed at a distance r = 1.4m exerting an electric field strength towards Q.
Hence
F = kQq/r²
K= 9× 10^9
Now recall that E = F/q (electric field due to that charge)
E =( kQq/r²)/q
E = kQ/r² substituting the values gave the answer above.
Answer:
.17Hz
Explanation:
The formula for frequency is f= 1/T , where T is the period.
f = 1/6 and 1/6 ≈ .17