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vredina [299]
3 years ago
14

I give a ball a push on an acclivity. The "start velocity" is on 7m/s. The time it took the ball to get back to me was 10 second

s. The acceleration is a constant. How much is the acceleration?
Physics
2 answers:
kozerog [31]3 years ago
8 0

Answer:

-1.4 m/s²

Explanation:

The initial velocity is 7 m/s.  When the ball rolls back, its velocity is -7 m/s.

Acceleration is change in velocity over change in time.

a = Δv / Δt

a = (-7 m/s − 7 m/s) / 10 s

a = -1.4 m/s²

Degger [83]3 years ago
3 0

Answer:

7÷10

Explanation:

initial velocity=7m/s

final velocity=0m/s

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2 years ago
At what time after being ejected is the boulder moving at a speed 20.7 m/s upward?
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The time after being ejected is the boulder moving at a speed 20.7 m/s upward is 2.0204 s.

<h3>What is the time after being ejected is the boulder moving at a speed 20.7 m/s upward?</h3>

The motion of the boulder is a uniformly accelerated motion, with constant acceleration

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downward (acceleration due to gravity).

By using Suvat equation:

v = u + at

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Therefore,

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The time after being ejected is the boulder moving at a speed 20.7 m/s upward is 2.0204 s.

The complete question is:

A large boulder is ejected vertically upward from a volcano with an initial speed of 40.0 m/s. Ignore air resistance. At what time after being ejected is the boulder moving at 20.7 m/s upward?

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