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Irina18 [472]
2 years ago
12

Point R is between points Q and S. Label the

Mathematics
1 answer:
3241004551 [841]2 years ago
8 0

The measure of angle QS based on the information given when Point R is between points Q and S is 11x + 35.

<h3>How to depict the information?</h3>

From the information given,

PR = 3x + 7

QR = 8x + 28

The value of QS will be:

PR + QR

= (3x + 7) + (8x + 28)

= 11x + 35

Learn more about angles QS on:

brainly.com/question/25716982

#SPJ1

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Act like it's a rectangle. The height is 10 because 7+3=10 and the length it 27. Multiply them for the are and you get 270 in. Then multiply 6x7=42 because that's the are of the space that is missing from the imaginary rectangle. Multiply by 2 (84 in.) because there are 2 missing spaces and subtract from 270= 186 inches is your answer.
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3 years ago
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Triangles O N M and S R Q are shown. Angles O N M and S R Q are congruent. The length of side N M is 10 and the length of side S
valina [46]

Answer:

Option C.

Step-by-step explanation:

In △ONM and △SRQ,

\angle ONM\cong \angle SRQ

NM=10

SR=20

NO=8

QR=x

We need to find the value of x that will make △ONM similar to △SRQ by the SAS similarity theorem.

According to SAS similarity theorem, two triangle are similar if two corresponding sides in both triangles are proportional and the included angle in both are congruent.

It is given that \angle ONM\cong \angle SRQ. So, both triangles are similar by SAS if

\dfrac{NO}{NM}=\dfrac{SR}{QR}

Substitute the given values.

\dfrac{8}{10}=\dfrac{20}{x}

8\times x=20\times 10

8x=200

Divide both sides by 8.

x=\dfrac{200}{8}

x=25

Therefore, the correct option is C.

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3 years ago
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A map uses a scale of 3/4 in = 80 miles. If two buildings are 60 miles apart in real life, how far apart would they be drawn on
Alla [95]

Given:

The scale of a map is \dfrac{3}{4}\ in=80\ miles.

The distance between two buildings is 60 miles.

To find:

The distance between the given building on the map.

Solution:

We have,

\dfrac{3}{4}\ in=80\ miles

It means, 80 miles in real life = \dfrac{3}{4}\ in on the map.

1 mile in real life = \dfrac{3}{4\times 80}\ in on the map.

60 mile in real life = \dfrac{3\times 60}{4\times 80}\ in on the map.

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Therefore, the buildings are \dfrac{9}{16}\ in apart on the map.

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