<span>The question is asking for the number of valence electron that are available fo bonding in bromine. Bromine belongs the group 7 of the periodic table, thus it has seven electrons in its outermost shell. At times, all these seven valence electrons can be involved in a chemical bonding in order to form an octet structure. Also, bromine can form a single covalent bond with other elements during chemical reactions. </span>
Answer:
i. n = 5
ii. ΔE = 7.61 × KJ/mole
Explanation:
1. ΔE = (1/λ) = -2.178 × ( - )
(1/434 × ) = -2.178 × ()
⇒ 434 × = (1/-2.178 × )
But, = 2
434 × = (1/2.178 × )
434 × × 2.178 × =
⇒ = 5
Therefore, the initial energy level where transition occurred is from 5.
2. ΔE = hf
= (hc) ÷ λ
= (6.626 × 10−34 × 3.0 × ) ÷ (434 × )
= (1.9878 × ) ÷ (434 × )
= 4.58 × J
= 4.58 × KJ
But 1 mole = 6.02×, then;
energy in KJ/mole = (4.58 × KJ) ÷ (6.02×)
= 7.61 × KJ/mole
Dmitri Mendeleev invented the periodic table.
Most likely the higher concentration of a reactant will increase the initial rate due to more collisions<span>
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Solid, liquid, and gas is the order
so solid is the highest, liquid is the middle, and gas is the lowest