Ask question

Ask question

All categories

2 years ago

5

A student heats a LaTeX: 2.5 g sample of calcium carbonate in a test tube. What mass of calcium oxide remains in the test tube w

hen the reaction is complete?
CaCO3(s) to CaO(s) + CO2(g)
Select one:
a) 1.4 g CaO
b)2.1 g CaO
c)2.5 g CaO
d)1.0 g CaO

2 answers:

Akimi4 [234]2 years ago

8 0

I got answer ‘a’ (1.4g)

polet [3.4K]2 years ago

3 0

Answer:

2.5

Explanation:

You might be interested in

What is the mass number of an atom with 17 protons, 17 electrons, and 20 neutrons?

astra-53 [7]

The mass number of this particular element is 37

An element with 17 protons will ALWAYS be chlorine.
The mass number is found by adding the element’s protons and neutrons.
protons+neutrons=mass number

Here is the math if needed,
17+20=37

Therefore the mass number is 37

I hope this helped!

3 0

3 years ago

1. An example of a polyatomic ion is:<br>a) SO²-4<br>b) Ca?<br>c) O2<br>d) NaCl

zlopas [31]

Answer:

A is the answer. Ca(calcium) is an element, O2 is a diatomic element, and NaCl is a compound composed of Na(sodium) and Cl(chlorine)

Explanation:

hopefully that helps!!!

8 0

2 years ago

The bobsled is an event in the winter Olympics. In this event, each sled and its riders speed down an icy track. Which factor(s)

goldenfox [79]

Answer:

Speed and Mass

3 0

2 years ago

Read 2 more answers

Name the salt used in plastering the fractured bone

Eddi Din [679]

Answer: Calcium Sulphate Hemihydrate

The compound of calcium which is used for plastering of fractured bones is Plaster of Paris. It is also called as Calcium Sulphate Hemihydrate.

3 0

2 years ago

a water sample is found to have a cl- content of 100ppm as nacl what is the concentration of chloride in moles per liter

ladessa [460]

Answer:

The concentration of chloride ion is $2.82\times10^{-3}\;mol/L$

Explanation:

We know that 1 ppm is equal to 1 mg/L.

So, the $Cl^-$ content 100 ppm suggests the presence of 100 mg of $Cl^-$ in 1 L of solution.

The molar mass of $Cl^-$ is equal to the molar mass of Cl atom as the mass of the excess electron in $Cl^-$ is negligible as compared to the mass of Cl atom.

So, the molar mass of $Cl^-$ is 35.453 g/mol.

Number of moles = (Mass)/(Molar mass)

Hence, the number of moles (N) of $Cl^-$ present in 100 mg (0.100 g) of $Cl^-$ is calculated as shown below:

$N=\frac{0.100\;g}{35.453\;g/mol}=2.82\times 10^{-3}\;mol$

So, there is $2.82\times10^{-3}\;mol$ of $Cl^-$ present in 1 L of solution.

5 0

3 years ago