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galina1969 [7]
3 years ago
5

A student heats a LaTeX: 2.5 g sample of calcium carbonate in a test tube. What mass of calcium oxide remains in the test tube w

hen the reaction is complete?
CaCO3(s) to CaO(s) + CO2(g)
Select one:
a) 1.4 g CaO
b)2.1 g CaO
c)2.5 g CaO
d)1.0 g CaO
Chemistry
2 answers:
Akimi4 [234]3 years ago
8 0
I got answer ‘a’ (1.4g)

polet [3.4K]3 years ago
3 0

Answer:

2.5

Explanation:

You might be interested in
H2S (g) + O2(g) -> SO2+ H2O, how many grams of O2 are needed to make 25.0 g of SO2 (Hint: balance the equation first)
vekshin1

Answer:

Hello

The answer is 18,7(b)

Explanation:we don't know the value of o² so at first we should put (x)instead of gr of o²and then write 1molO²/32grO²×2mol SO²/3mol O²×64gr SO²/1molSO²=25 gr SO².and then just find the value of (x).

5 0
3 years ago
What is the chemical formula for 8.6 mol of sulfur and 3.42 mol of phosphorus
adell [148]

The chemical formula for the compound containing 8.6 mol of sulfur and 3.42 mol of phosphorus is P₂S₅

<h3>How do I determine the formula of the compound?</h3>

From the question given above, the following data were obatined:

  • Sulphur (S) = 8.6 moles
  • Phosphorus (P) = 3.42 mole
  • Chemical formula =?

The chemical formula of the compound can be obtained as follow:

Divide by their molar mass

S = 8.6 / 32 = 0.26875

P = 3.42 / 31 = 0.11032

Divide by the smallest

S = 0.26875 / 0.11032 = 2.44

P = 0.11032 / 0.11032 = 1

Multiply by 2 to express in whole number

S = 2.44 × 2 = 5

P = 1 × 2 = 2

Thus, the chemical formula is P₂S₅

Learn more about empirical formula:

brainly.com/question/9459553

#SPJ1

5 0
1 year ago
If nitrogen and hydrogen combine in a combustion reaction, what would the product of the reaction be?
kow [346]

Co2

Explanation:

CH4 (g) + 2 O2 (g) → CO2 (g) + 2 H2O (l)

4 0
3 years ago
Read 2 more answers
To measure the speed of a car, we use miles per hour (miles/hour or mi/h or mph). To measure the rate of a reaction we use molar
arsen [322]

Answer:

Part A: 47.8 mi/h

Part B: 0.072 M/s

Part C: 0.144 M/s

Explanation:

Part A

The average speed or velocity (V) is the variation of the space divided by the variation of the time:

V = (241 - 2)/(8 -3)

V = 47.8 mi/h

Part B

As Part A, the average rate (r) of formation of I2 is the variation of the concentration divided by the variation of time:

r = (1.83 - 1.11)/(15 - 5)

r = 0.072 M/s

Part C

The rates of the substances are proportional of their number of moles (n) which are their coefficient, so:

rI2/nI2 = rHCl/nHCl

0.072/1 = rHCl/2

rHCl = 2*0.072

rHCl = 0.144 M/s

7 0
3 years ago
f 23.6 mL of 0.200 M NaOH is required to neutralize 10.00 mL of a H3PO4 solution , what is the concentration of the phosphoric a
Eduardwww [97]

Answer:

Explanation:

H3PO4(aq) + 3NaOH(aq) → Na3PO4(aq) + 3H2O(l)

mole of NaOH = 23.6 * 10 ⁻³L * 0.2M

= 0.00472mole

let x be the no of mole of H3PO4 required of  0.00472mole of NaOH

3 mole of NaOH required ------- 1 mole of H3PO4

0.00472mole of NaOH ----------x

cross multiply

3x = 0.0472

x = 0.00157mole

[H3PO4] = mole of H3PO4 / Vol. of H3PO4

= 0.00157mole / (10*10⁻³l)

= 0.157M

<h3>The concentration of unknown phosphoric acid is  0.157M</h3>
7 0
3 years ago
Read 2 more answers
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