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Sergeu [11.5K]
3 years ago
8

1 point

Physics
1 answer:
nekit [7.7K]3 years ago
6 0

Answer:

weight/mass = gravitational field strength

Given :

Weight of stone = 5.7 N

Gravitational field strength (g) = 10 N/kg

Taking Mass of stone x

=> 5.7/x = 10

x = 10 * 5.7

x = 57 kg

Therefore mass of stone is 57 kg

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Observing neutrinos from the Sun is an important way to check the fusion rate, but it can be very tough to build a machine that
Vika [28.1K]

Answer:

The trouble that the most recent experiment, Borexino, have to overcome was that

neutrinos hardly interact with matter and so radioactive decay of ant material inside the detector could look exactly like a neutrino interaction too

5 0
3 years ago
(this is somehow part of my science unit, dont ask why)
nirvana33 [79]

Answer:

 Height of coffee mug = 5 cm

Explanation:

  Changing all the data given in to unit cm

              50 mm = 5 cm

              20 cm  = 20 cm

              8 m    = 800 cm

              0.1 km = 100 m = 10000 cm

Since we need to find the height of coffee mug, it's height will not be more than 10 cm.

  So 5 cm is the correct choice.

6 0
4 years ago
An egg is Free Falling Down from a nest in a tree (neglect air resistance)​
DedPeter [7]

We are to calculate the acceleration.

Answer:

-9.8 m/s²

Explanation:

Since the egg is in a free fall, it means that the force due to gravity will be equal to the normal force.

Now,

Force due to gravity: F_g = mg

Normal force; F_n = ma

Thus;

mg = ma

m will cancel out to get

g = a

Since it is a free fall motion, then gravity is negative;

-g = a

g has a constant value of 9.8 m/s². Thus;

a = -9.8 m/s²

5 0
3 years ago
Two planets are orbiting a star. Planet A is closer to the star than Planet B. Which description explains the expected motion of
77julia77 [94]
<span>Planet A orbits faster than Planet B, i believe is the answer. hope that helps

</span>
6 0
3 years ago
Read 2 more answers
A wire of length 26.0 cm carrying a current of 5.77 mA is to be formed into a circular coil and placed in a uniform magnetic fie
Olin [163]

Answer:

The maximum torque is  \tau_{max} =  1.139 *10^{-7} \ N \cdot m

Explanation:

From the question we are told that

   The length of the wire is  l =  26.0 \ cm  =  0.26 \  m

     The current flowing through the wire is  I  = 5.77mA  =  5.77 *10^{-3} \ A

      The magnetic field is  B = 3.67 \ mT  =  3.67 *10^{-3 } T

         

The maximum torque is mathematically evaluated as

        \tau_{max} =   \mu B  

Where \mu  is the magnetic dipole moment which is mathematically represented as

        \mu  =  \frac{I l^2}{4 \pi n }

Where n is the number of turns which from the question is  1

    substituting values

       \mu  =  \frac{ 5.77 *10^{-3}  *  0.26^2}{4  * 3.142* 1 }

     \mu  =  3.10 4*  10^{-5}  A m^2

Now  

      \tau_{max} =  3.104 *10^{-5} * 3.67 *10^{-3}  

      \tau_{max} =  1.139 *10^{-7} \ N \cdot m  

7 0
3 years ago
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