y = x² - 4x + 4
0 = x² - 4x + 4
0 = x² - 2x - 2x + 4
0 = x(x) - x(2) - 2(x) - 2(-2)
0 = x(x - 2) - 2(x - 2)
0 = (x - 2)(x - 2)
0 = (x - 2)²
0 = x - 2
+ 2 + 2
2 = x
(x, y) = (2, 0)
Answer:
there are 2.25 one-thirds in a three-fourth.
Hope this helps you out!
Answer:
Sorry but the correct answer is (x+3)2+(y−1)2=81
Step-by-step explanation:
Because the radius squared is the answer of the equation
Answer:
A. (x−2y)(y−3x)
=(x+−2y)(y+−3x)
=(x)(y)+(x)(−3x)+(−2y)(y)+(−2y)(−3x)
=xy−3x2−2y2+6xy
=−3x2+7xy−2y2
B. (2p+3)(p2−4p−7)
=(2p+3)(p2+−4p+−7)
=(2p)(p2)+(2p)(−4p)+(2p)(−7)+(3)(p2)+(3)(−4p)+(3)(−7)
=2p3−8p2−14p+3p2−12p−21
=2p3−5p2−26p−21
Hope it helps
Please mark me as the brainliest
Thank you
The equation of the tangent line of f(x) is given by y = f'(x)x + c
f(x) = 2sin x
f'(x) = 2cos x
At x = pi/3
f'(pi/3) = 2 cos(pi/3) = 1
f(pi/3) = 2 sin(pi/3) = √3
√3 = 1(π/3) + c
c = √3 - π/3
Therefore, required equation is
y = x + √3 - π/3
