Ask question

Ask question

All categories

2 years ago

5

Which graph represents the function

%201" id="TexFormula1" title="g(x) = \sqrt{x - 1} + 1" alt="g(x) = \sqrt{x - 1} + 1" align="absmiddle" class="latex-formula">

1 answer:

Olin [163]2 years ago

7 0

Answer:

The bottom-left graph.

Step-by-step explanation:

g(1) = 0+1 = 1 => g(1) = 1

=> (1,1) ∈ Gf

You might be interested in

Phil and Matt made a total of $72.00 selling the cookies. How many cookies

marshall27 [118]

Answer:

36

Step-by-step explanation:

It would only be 36 if they split the amount though

5 0

2 years ago

You read 105 pages of a novel over 7 days what is the mean number of pages you read each day

Zolol [24]

105/7=15
so you will have to read 15 pages per day

3 0

3 years ago

Read 2 more answers

The students of a middle school are selling homemade candles to raise money for a charity. The candles will be sold for $7 each.

Tom [10]

I think the answer is D , I hope this helped. If not I’m sorry I tried my hardest

6 0

2 years ago

Read 2 more answers

72.1 written as a fraction

kaheart [24]

It is 72 1/10. This is because 72 is a whole number and point one would be tenths.

5 0

3 years ago

Read 2 more answers

G(x) = -2x^3 – 15x^2 + 36x

shusha [124]

Consider the function $G(x) = -2x^3 - 15x^2 + 36x.$ First, factor it:

$G(x) = -2x^3 - 15x^2 + 36x=-x(2x^2+15x-36)=\\ \\=-x\cdot 2\cdot \left(x-\dfrac{-15-\sqrt{513}}{4}\right)\cdot \left(x-\dfrac{-15+\sqrt{513}}{4}\right).$

The x-intercepts are at points $\left(\dfrac{-15-\sqrt{513} }{4},0\right),\ (0,0),\ \left(\dfrac{-15+\sqrt{513} }{4},0\right).$

1. From the attached graph you can see that

function is positive for $x\in \left(-\infrty, \dfrac{-15-\sqrt{513} }{4}\right)\cup \left(0,\dfrac{-15+\sqrt{513} }{4}\right);$
function is negative for $x\in \left(\dfrac{-15-\sqrt{513} }{4},0\right)\cup \left(\dfrac{-15+\sqrt{513} }{4},\infty\right).$

2. Since

$G(-x) = -2(-x)^3 - 15(-x)^2 + 36(-x)=2x^3-15x^2-36x\neq G(x)\ \text{and }\neq -G(x)$ the function is neither even nor odd.

3. The domain is $x\in (-\infty,\infty),$ the range is $y\in (-\infty,\infty).$

8 0

3 years ago

Read 2 more answers