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madreJ [45]
3 years ago
11

How many houses are on Prince Street?

Mathematics
2 answers:
Thepotemich [5.8K]3 years ago
7 0

Answer:

25 houses

Step-by-step explanation:

You need to add up all the houses and u will get the ans..

Have a good day !!

Hope this helps..

<h2>                   <em>      </em><u><em>Pls mark my ans as branliest :)</em></u></h2><h2><u><em>If u mark my ans as brainliest then u are the "bestestest " person in the world  </em></u><u>:)</u></h2>
sertanlavr [38]3 years ago
5 0

Answer:

25 houses on prince street

Step-by-step explanation:

add them up and bam

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Gnesinka [82]
A straight angle is equal to 180 degrees. 180-80=100. 100-60=40. so y=40. vertical angles are congruent so x=40 degrees.
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A rectangle is placed around a semicircle as shown below. The length of the rectangle is 8 cm. Find the area of the shaded regio
icang [17]

Answer:

Area of the shaded region = 6.88 cm²

Step-by-step explanation:

Area of the shaded region = Area of the rectangle - Area of the semicircle

Area of the rectangle = Length × Width

Length of the rectangle = AD = 8 cm

Width of the rectangle = OP = 4 cm [OP, OB and OC are the radii of the circle which are equal in measures]

Area of the rectangle = 8 × 4 = 32 cm²

Area of the semicircle = \frac{1}{2}\pi r^{2}

                                     = \frac{1}{2}\pi (OP)^{2}

                                     = \frac{1}{2}\pi (4)^{2}

                                     = 25.12 cm²

Area of the shaded region = 32 - 25.12

                                              = 6.88 cm²

3 0
3 years ago
To make 2 batches of nut bars, Jayda needs to use 4 eggs. How many eggs are used in each batch
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3 0
3 years ago
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A system for tracking ships indicated that a ship lies on a hyperbolic path described by 5x2 - y2 = 20. the process is repeated
zysi [14]
Answer:
The ship is located at (3,5)

Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III

Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II

To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.

Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9

We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3

Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5

Based on the above, the position of the ship is (3,5).

Hope this helps :)
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3 years ago
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