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Alisiya [41]
3 years ago
12

If I have 15.40mL of 1.4M HBr(aq) and add 22.10mL KOH what is the molarity ofKOH being used?​

Chemistry
1 answer:
postnew [5]3 years ago
8 0

The molarity of KOH is 0.98 M.

<u>Explanation:</u>

KOH + HBr →KBr + H₂O

As per the above reaction, equal moles of KBr and HBr reacts to form 1 mole of KBr and 1 mole of water. We have to find the molarity of KOH by using the law of Volumetric analysis using the equation as,

V1M1 = V2M2

Here V1 and M1 are the volume and molarity of HBr.

V2 and M2 are the volume and molarity of KOH .

We can find the molarity of KOH as,

$ M2= \frac{V1\times M1}{V2}

Plugin the values as,

$ M2 = \frac{15.40 ml \times 1.4 M}{22.10 ml}

    =  0.98 M

So the molarity of KOH is 0.98 M.

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How many grams of Fe2+ are there in 0.003109 moles of Fe2+?
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Answer: 0.174 g

Explanation:

First of all understand that charge on an atom like here 2+ will not vary molar mass. because ions are formed by loss or gain of electrons and electrons do not contribute to the mass of an atom or ion. so losing or gaining electron doesnt create any difference.

molar mass of Fe, i.e. mass of 1 mole of Fe is 56 g. So, mass of 1 mole of Fe2+ will also be 56 g.

given is 0.003109 moles of Fe2+,

Use maths,

1 mole of Fe2+ weighs 56 g

So, 0.003109 moles will weigh = (56 g / 1 mol ) x 0.003109 = 0.174 g.

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Alum is a compound used in a variety of applications including cosmetics, water purification, and as a food additive. It can be
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yield = 52.23 %

Explanation:

We have the following chemical reaction:

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mass of aluminium = mass of bottle with aluminium pieces - bottle mass

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mass of alum = mass of bottle with final product - bottle mass

mass of alum = 19.0414 - 9.8981 = 9.1433 g

number of moles = mass / molecular weight

number of moles of aluminium = 0.9974 / 27 = 0.03694 moles

number of moles of alum (practical) = 9.1433 / 474 = 0.01929 moles

To calculate the theoretical quantity of alum that should be obtained from 0.03694 moles of aluminium we devise the following reasoning:

if       2 moles of aluminium produce 2 moles of alum

then 0.03694 moles of aluminium produce X moles of alum

X = (0.03694 × 2) / 2 = 0.03694 moles of alum (theoretical)

yield = (practical quantity / theoretical quantity) × 100

yield = (0.01929 /  0.03694) × 100

yield = 52.23 %

Learn more about:

reaction yield

brainly.com/question/7786567

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Mole are in 5.1 grams of beryllium ?
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