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Alisiya [41]
3 years ago
12

If I have 15.40mL of 1.4M HBr(aq) and add 22.10mL KOH what is the molarity ofKOH being used?​

Chemistry
1 answer:
postnew [5]3 years ago
8 0

The molarity of KOH is 0.98 M.

<u>Explanation:</u>

KOH + HBr →KBr + H₂O

As per the above reaction, equal moles of KBr and HBr reacts to form 1 mole of KBr and 1 mole of water. We have to find the molarity of KOH by using the law of Volumetric analysis using the equation as,

V1M1 = V2M2

Here V1 and M1 are the volume and molarity of HBr.

V2 and M2 are the volume and molarity of KOH .

We can find the molarity of KOH as,

$ M2= \frac{V1\times M1}{V2}

Plugin the values as,

$ M2 = \frac{15.40 ml \times 1.4 M}{22.10 ml}

    =  0.98 M

So the molarity of KOH is 0.98 M.

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