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Alisiya [41]
3 years ago
12

If I have 15.40mL of 1.4M HBr(aq) and add 22.10mL KOH what is the molarity ofKOH being used?​

Chemistry
1 answer:
postnew [5]3 years ago
8 0

The molarity of KOH is 0.98 M.

<u>Explanation:</u>

KOH + HBr →KBr + H₂O

As per the above reaction, equal moles of KBr and HBr reacts to form 1 mole of KBr and 1 mole of water. We have to find the molarity of KOH by using the law of Volumetric analysis using the equation as,

V1M1 = V2M2

Here V1 and M1 are the volume and molarity of HBr.

V2 and M2 are the volume and molarity of KOH .

We can find the molarity of KOH as,

$ M2= \frac{V1\times M1}{V2}

Plugin the values as,

$ M2 = \frac{15.40 ml \times 1.4 M}{22.10 ml}

    =  0.98 M

So the molarity of KOH is 0.98 M.

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The molar mass of I2 is 253.80 g/mol, and the molar mass of NI3 is 394.71 g/mol. How many moles of I2 will form 3.58 g of NI3?
Nat2105 [25]
To answer the problem above first we need to find the difference of molar mass of NI3 from I2, 394.71 g/mol - 253.80 g/mol = 140.91 g/mol. Knowing the molar mass of the difference of NI3 from I2, in equation mass (g) / moles (mol) = molar mass, then we substitute. 3.58g / moles = 140.91 g/mol.
moles = 3.58 / 140.91 = 0.025 moles.
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If the caterpillar keeps moving at the same speed, how long will it take to travel 6cm?
Solnce55 [7]

It will take 15 s to travel 6 cm

<h3>Further explanation</h3>

Given

distance versus time graph

Required

time travel

Solution

Caterpillar motion is a straight motion with a constant speed, so that the graph between distance and time forms a diagonal line

If we look at the graph, we can determine the time taken when the distance reaches 6 cm (y axis) by drawing a line to the diagonal line and cutting the x-axis as time, and we get 15 s

Or we can also use the formula for motion at constant speed:

d = v x t

With v at point 2,5 of 2/5 m / s, so the time taken:

\tt t=\dfrac{d}{v}=\dfrac{6}{2/5}=15~s

4 0
3 years ago
The compound gallium phosphide () is a compound semiconductor having mixed ionic and covalent bonding. The electronegativities f
9966 [12]

Answer:

0.08875

Explanation:

Hello,

In this case, the first step is to compute the difference in the electronegativity for the formed bond between gallium and phosphorous by:

\Delta E=2.1-1.6\\\\\Delta E=0.5

Thus, we can compute the percentage of ionic character by:

\%\  ionic\ character=16\Delta E +3.5 (\Delta E)^2\\\\\%\  ionic\ character=16*0.5+3.5*0.5^2\\\\\%\  ionic\ character=8.875\%

So the fraction is just:

\frac{8.875}{100}=0.08875

Which has sense since gallium phosphide is a non-polar compound.

Regards.

3 0
3 years ago
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