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Virty [35]
3 years ago
15

PLEASE HELP ME!!

Chemistry
2 answers:
mrs_skeptik [129]3 years ago
6 0

Answer:

The answer to this question is D.

Explanation: We know that only plants have a cell wall so that is helpful and we know that plants are green because of their chloroplast. So the answer is D, cell wall, and chloroplast.

LUCKY_DIMON [66]3 years ago
4 0

Answer:

A

Explanation:

plant cells have a nucleus, which controls the cells activities. and the chloroplast contains a green pigment called the chlorophyll and is where photosynthesis occurs.

A animal cell does not have a nuclues, making it Prokaryotic.

Hoping i was of use :)

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Water near the poles often have higher salinity because Cold polar air cools the water and lowers its temperature, increasing its salinity. Fresh water freezes out of seawater to become sea ice, which also increases the salinity of the remaining water.

Understands! ♥

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Which of the following is a valid mole ratio from the balanced equation 2C3H6 + 902 - 6CO2 + 6H20? (4 points)
erastovalidia [21]

Answer:

6 mol H, 9 mol O2

Explanation:

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6 0
2 years ago
The combustion of 0.1240 kg of propane in the presence of excess oxygen produces 0.3110 kg of carbon dioxide. What is the limiti
nadezda [96]

Answer:

The limiting reactant is the propane gas, C₃H₈ while the percentage yield is 83.77%

Explanation:

Here we have

Propane gas with molecular formula C₃H₈, molar mass  = 44.1 g/mol combining with O₂ as follows

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

Therefore, 1 mole of C₃H₈  combines with 5 moles of O₂ to produce 3 moles CO₂ and 4 moles of H₂O

Mass of propane = 0.1240 kg = 124.0 g

Number of moles of propane = mass of propane/(molar mass of propane)

The number of moles of propane = 124/44.1 = 2.812 moles

The molar mass of CO₂ = 44.01 g/mol

Mass of CO₂ = 0.3110 kg = 311.0 g

Therefore, number of moles of CO₂ = mass of CO₂/(molar mass of CO₂)

The number of moles of CO₂ = 311.0 kg/ 44.01 g/mol = 7.067 moles

Therefore, since 1 mole of propane produces 3 moles of CO₂, 2.812 moles of propane will produce 3 × 2.812 moles or 8.44 moles of CO₂

Therefore;

The limiting reactant is the propane gas, C₃H₈, since the oxygen is in excess

Hence

The \ percentage \ yield = \frac{Actual \, yield}{Theoretical \, yield} \times 100 = \frac{7.067}{8.44} \times 100 = 83.77 \%

The percentage yield = 83.77%.

7 0
3 years ago
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