Answer:
Ix = Iy =
Radius of gyration x = y = 
Step-by-step explanation:
Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.
Mass of disk = ρπR2
Moment of inertia about its perpendicular axis is
. Moment of inertia of quarter disk about its perpendicular is
.
Now using perpendicular axis theorem, Ix = Iy =
=
.
For Radius of gyration K, equate MK2 = MR2/16, K= R/4.
Answer:
the diagram represents the process of enlarging a rectangle using a scale factor of 3. the width of the original rectangle must be:
Step-by-step explanation:
Answer:
You keep adding 15.
Step-by-step explanation:
5+15=20
20+15=35
35+15=50
50+15=65
Answer:
<em>2</em><em>5</em><em>0</em><em>°</em>
<em>There</em><em> </em><em>are</em><em> </em><em>2</em><em>5</em><em>0</em><em>°</em><em>…</em><em>…</em><em>…</em><em>…</em><em>…</em>