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3 years ago

I need the help for this please!

Mathematics

2 answers:

alexandr402 [8]3 years ago

7 0

Just divide your answer but what the probability is and take that fraction and reduce it to get the first fraction

Morgarella [4.7K]3 years ago

4 0

Cross multiply then solve the equation.

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What is the slope of a line passing through the points (2, 5) and (0, −4)?

natima [27]

M=9/2 sorry if it’s wrong

4 0

3 years ago

Simplify 35.36 over 17

rjkz [21]

Answer:

it's

2.08

Step-by-step explanation:

 $35.36 \div 17 = 2.08$ 

so I think think this answer will helpful to u....the answer is 2.08

4 0

4 years ago

A personnel manager is concerned about absenteeism. She decides to sample employee records to determine if absenteeism is distri

nlexa [21]

Answer:

$df=categor-1=6-1=5$

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got $\chi^2_{critc}= 11.0705$

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Solution to the problem

For this case we want to test:

H0: Absenteeism is distributed evenly throughout the week

H1: Absenteeism is NOT distributed evenly throughout the week

We have the following data:

Monday Tuesday Wednesday Thursday Friday Saturday Total

12 9 11 10 9 9 60

The level of significance assumed for this case is $\alpha=0.05$

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{60}{6}= 10$ and the expected value is the same for all the days since that's what we want to test.

now we can calculate the statistic:

$\chi^2 = \frac{(12-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(11-10)^2}{10}+\frac{(10-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(9-10)^2}{10}=0.8$

Now we can calculate the degrees of freedom (We know that we have 6 categories since we have information for 6 different days) for the statistic given by:

$df=categor-1=6-1=5$

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got $\chi^2_{critc}= 11.0705$

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

4 0

3 years ago

Which equation is equivalent to 3 (2x + 10) -10x = 26 ?

mrs_skeptik [129]

Answer:

The answer to this problem is B. Although you have a typo error with "-4" I believe it is "-4x",

Step-by-step explanation:

The equation is set with distributive property. Simplify that first and then move on to adding like terms.

3(2x + 10) - 10x = 26.

6x + 30 - 10x = 26.

-4x + 30 = 26.

The only equation that looks equivalent is -4x + 30 = 26 in B.

For A, it would of been correct if -10x was 10x, but it is not so mark it out.

For C, it would of been correct if there was no -10x and if there was a -20, but this is not true so mark it out as well.

For D, it would of been correct if there was a -20, but since there is no -20, this is wrong like A and C.

So B is the best option.

3 0

4 years ago

Which of the following values are in the range of the function graphed below? Check all that apply

timurjin [86]

Answer:

-10-10=20

10+10=20

20/20=0

8 0

3 years ago